Mass spectrum of Dodecane will give following information.
1 ) Molecular Peak or Parent Peak:
The Parent peak will appear at m/z = 170. The intensity of this peak will be very weak.
2) Fragments:
Usually the fragments of such long chain alkanes appear with spacing of 14 amu, Hence, the peaks in dodecane will be as follow,
170 - 156 - 142 - 128 - 114 - 100 - 86 - 72 - 58 - 44 - 30 - 16
3) Base Peak:
Most probably the Base peak will appear at m/z = 57. This peak is due to the formation of tertiary butyl cation as the intensity mainly depends upon the stability of cation. So this cation might form due to rearrangment giving the intensity of 100%.
The same number of valence electrons exists in the same family of elements in the periodic table. In finding the answer to this problem, we just have to find the pair that belongs to the same family in the periodic table. The same family means same column. Among these, Oxygen and lead (Pb) are in the same family. This pair is the answer.
Answer:
This is an acid-base reaction (neutralization): H 2SO 4 is an acid, Ca(OH) 2 is a base.
...
1 H2SO4 + Ca(OH)2 → H2O + CaSO4
2 H2SO4 + Ca(OH)2 → CaSO4 + HOH
3 H2SO4 + Ca(OH)2 → H2O + CaOH2SO4
4 H2SO4 + Ca(OH)2 → H2O + Ca(HSO4)2
5 H2SO4 + Ca(OH)2 → H2O + (CaOH)2SO4
Explanation:
Answer:
<h3>The answer is 2.50 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 25 g
volume = 10 mL
We have
We have the final answer as
<h3>2.50 g/mL</h3>
Hope this helps you
201 grams.
<h3>Explanation</h3>
What's the formula of Silver Sulfide?
Consider the two kinds of ions in silver sulfide:
- Silver ions , and
- Sulfide ions .
The charge on the two types of ions should balance. The charge on each sulfide ion is twice as much as that on a silver ion. There needs to be <em>two</em> silver ions for each sulfide ion.
Hence the formula: .
How many <em>moles </em>of formula units in 174 grams of Ag₂S.
Relative atomic mass from a modern periodic table:
- Silver Ag: 107.868;
- Sulfur S: 32.06;
- Chlorine Cl: 35.45.
.
.
How many <em>moles</em> of AgCl formula units will be formed from 174 grams of Ag₂S?
The question doesn't mention the other product in this reaction. Finding that product isn't a must as long as all Ag from Ag₂S end up in AgCl.
.
We are trying to answer the question: how many moles of AgCl does <em>each</em> mole formula unit of Ag₂S produce. Thus, assign a coefficient of <em>one</em> to Ag₂S.
There are two silver atoms in each formula unit Ag₂S. Both would end up in AgCl. However, there's only one silver atom in each formula unit of AgCl. Two Ag atoms would make two formula units of AgCl. In other words, each mole formula units of Ag₂S would produce <em>two</em> moles formula units of AgCl.
.
There are 0.702 moles of Ag₂S formula units in 174 grams of the compound. That would lead to of AgCl.
What's the mass of 1.40 mol of AgCl?
.
.