Answer: When the effective nuclear charge decreases, electrons are loosely held thereby making it easier for electrons to be lost.
Explanation:
Answer:
The answer is 916.67 g
Explanation:
48.0 wt% NaOH means that there are 48 g of NaOH in 100 g of solution. With this information and the molecular weight of NaOH (40 g/mol), we can calculate the number of mol there are in 100 g of this solution:
x 
= 0.012 mol NaOH/100 g solution
Finally, we need 0.11 mol in 1 liter of solution to obtain a 0.11 M NaOH solution.
0.012 mol NaOH ------------ 100 g solution
0.11 mol NaOH------------------------- X
X= 0.11 mol NaOH x 100 g/ 0.012 mol NaOH= 916.67 g
We have to weigh 916.67 g of 48.0%wt NaOH and dilute it in a final volume of 1 L of water to obtain a 0.11 M NaOH solution.
It will be K-potassium because when you go down a group the electronegativty gets bigger while when you go across the period they get smaller because of the valence electrons. Group 8 has the lowest electronegativty because they have a full outer shell. From left to right on the periodic table it decreases but from top to bottom it increases.
They come up with a hypothesis (question to investigate), then they work out what variables and what they will be measuring, keeping the same and changing in the experiment
Answer:
this reaction is a double displacement reaction in which, Aluminium nitrate reacts with hydrogen sulphide to form nitric acid and Aluminium sulphide.
here is the balanced chemical equation for the above reaction :
2 Al (NO3)3 + 3 H2S -> 6 HNO3 + Al2S3
