Answer:
p=1/2*3.14+d
1/2*3.14*19.5=30.615
=30.615+39
=69.615
=69.6
Step-by-step explanation:
since it's half a circle we take the formula of acricle to be half
Answer:
RT = 12 units
Step-by-step explanation:
From the figure attached,
ΔSRQ is right triangle.
m∠R = 90°
An altitude has been constructed from point T to side SQ.
m∠RTQ = 90°
By applying geometric mean theorem in triangle SRQ,


x² = 16 × 9
x² = 144
x = √144
x = 12
Therefore, length of altitude RT is 12 units.
The pH of the weak acid is 3.21
Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :
![[H^{+}]=\sqrt{Ka . Ma}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D%5Csqrt%7BKa%20.%20Ma%7D)
where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.
Since we know the concentration of H+, the pH can be calculated by using
pH = -log[H+]
From question above, we know that :
Ma = 0.0250M
Ka = 1.5 x 10¯⁵
By using the equation, we can determine the concentration of [H+]
[H+] = √(Ka . Ma)
[H+] = √(1.5 x 10¯⁵ . 0.0250)
[H+] = 6.12 x 10¯⁴ M
Substituting the value of [H+] to get the pH
pH = -log[H+]
pH = -log(6.12 x 10¯⁴)
pH = 3.21
Hence, the pH of the weak acid c3h7cooh is 3.21
Find more on pH at: brainly.com/question/14466719
#SPJ4
Step-by-step explanation:
bsbdbxbshzb jdjxhdjzbe
<span>b. 60 m2
</span>Find the area of the figure. Assume all figures are made up of parallelograms and triangles.
NOT:
b. 60 m2
c. 108 m2
<span>d. 135 m2 please help</span>
<span>
</span>