The equation of circle in standard form is 
<h3><u>Solution:</u></h3>
Given that circle having center point (3,7) and the radius r = 4
To find: equation of circle in standard form
<em><u>The equation of circle is given as:</u></em>

Where center (h,k) and radius r units
Given that center point (h , k) = (3, 7) and radius r = 4 units
Substituting the values in above equation of circle,

Thus the equation of circle in standard form is 
-4(x-8) + 3(2x+5)
-4x+32 + 6x+15
2x+47
2(10)+47
20+47
67
Answer:
the answer should be conjecture sum hehehe
Step-by-step explanation:
this is a veryyyy hard questionnnnnnn
Answer:
- length: 8
- end points: (-8, 1), (0, 1)
Step-by-step explanation:
In the quadratic form ...
(x -h)² = 4p(y -k)
The value 4p is the length of the latus rectum. It also tells the distance between the vertex (h, k) and the focus (h, k+p).
<h3>Application</h3>
The value of 4p is given as 8. This means p = 8/4 = 2.
The length of the latus rectum is 8.
The end points of the latus rectum have the same y-value as the focus:
y = k +p = -1 +2 = 1
The end points of the latus rectum have x-values that are h±2p.
x = h ± 2p = -4 ± 2·2 = {-8, 0}
The end points of the latus rectum are (-8, 1) and (0, 1).