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jeka57 [31]
3 years ago
12

Answer asap pls i give brainliest

Chemistry
1 answer:
Troyanec [42]3 years ago
3 0

Answer:

B. Revolution is a planet's movement around the sun causing four seasons the occur. Rotation is the spinning of the planet on its axis causing day and night.

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Compare the properties of protons neutrons and electrons
butalik [34]
Protons are positively charged. Neutrons have no charge. Electrons have a negative charge. Protons and neutrons are in the nucleus. Electrons revolve around the nucleus. 
6 0
4 years ago
Read 2 more answers
Which Statement correctly describes protons
____ [38]

Answer:

D.  

They have a positive charge and are present in the nucleus of an atom along with the neutrons.

explanation:

Protons have a positive charge.

7 0
3 years ago
Can u help me with this
dolphi86 [110]

Answer:

c

Explanation:

the reason is because your a homosiejenenddj

8 0
3 years ago
A 7.5 L cylinder contains 5 moles of gas at a temperature of 274°C. What is its pressure in kiloPascals (kPa)?
AleksAgata [21]
<h3><u>Answer;</u></h3>

 = 3032.15 kPa

<h3><u>Explanation;</u></h3>

Using the equation;

PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.

Volume = 7.5 L, T = 274 +273 = 547 K, N = 5 moles

Therefore;

Pressure = nRT/V

               = (5 × 0.08206 × 547)/7.5 L

               = 29.925 atm

But; 1 atm = 101325 pascals

Hence; Pressure = 3032150.63 pascals

                            <u>= 3032.15 kPa</u>

               

3 0
3 years ago
A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor
AlexFokin [52]

Answer : The partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of C_2HBrClF_3 = 15.0 g

Mass of O_2 = 22.6 g

Molar mass of C_2HBrClF_3 = 197.4 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_2HBrClF_3 and O_2.

\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole

and,

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole

Now we have to calculate the mole fraction of C_2HBrClF_3 and O_2.

\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971

and,

\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903

Now we have to partial pressure of C_2HBrClF_3 and O_2.

According to the Raoult's law,

p^o=X\times p_T

where,

p^o = partial pressure of gas

p_T = total pressure of gas

X = mole fraction of gas

p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T

p_{C_2HBrClF_3}=0.0971\times 862torr=84torr

and,

p_{O_2}=X_{O_2}\times p_T

p_{O_2}=0.903\times 862torr=778torr

Therefore, the partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

6 0
3 years ago
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