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hodyreva [135]
3 years ago
9

Can you find five solutions to the function: y=3x-7?​

Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0

The five solutions are :

  • (2 , -1)

  • (3 , 2)

  • (4 , 5)

  • (0 , -7)

  • (1 , -4)
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Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 134 millimeters,
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; 134

a:8

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3.6

3.6

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[ - ]]p(-2.98 ' z ' 2.98)]

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6 0
3 years ago
I need the answer fast please find the tan(b)
PSYCHO15rus [73]

Answer:

\sf \dfrac{17}{25}

Step-by-step explanation:

<h3>Trigonometry:</h3>

    \sf \boxed{\bf Tan \ B=\dfrac{oppoiste \ side \ to \ Tan \ B}{hypotenuse}}

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6 0
1 year ago
Show your work.
Doss [256]

Answer:

1= 2,400 feet

2= 154 meters

3= 120 pints

4= 2. 056 centigrams

5= 16.1 C

6= 50F

7= -2.8C

1= multiply the length value by 3

2= divide the length value by 10

3= multiply the volume value by 8

4= divide the mass value by 10

5= Take the °F temperature and subtract 32. Multiply this number by 5. Divide this number by 9 to obtain your answer in °C.

6= multiply the temperature in degrees Celsius by 2, and then add 30 to get the (estimated) temperature in degrees Fahrenheit.

6 0
3 years ago
Read 2 more answers
Box of 15 gadgets is known to contain 5 defective gadgets if 4 gadgets are drawn at random what is the probability of finding no
baherus [9]

To solve this problem, we make use of the Binomial Probability equation which is mathematically expressed as:

P = [n! / r! (n – r)!] p^r * q^(n – r)

where,

n = the total number of gadgets = 4

r = number of samples = 1 and 2 (since not more than 2)

p = probability of success of getting a defective gadget

q = probability of failure = 1 – p

 

Calculating for p:

p = 5 / 15 = 0.33

So,

q = 1 – 0.33 = 0.67

 

Calculating for P when r = 1:

P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3

P (r = 1) = 0.3970

 

 

Calculating for P when r = 2:

P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2

P (r = 2) = 0.2933

 

Therefore the total probability of not getting more than 2 defective gadgets is:

P = 0.3970 + 0.2933

P = 0.6903

 

Hence there is a 0.6903 chance or 69.03% probability of not getting more than 2 defective gadgets.

5 0
3 years ago
Find the difference.<br><br> (5x2 - 3x + 7) - (3x2 + 4x - 5)
Katena32 [7]

Answer:

16-7x

Step-by-step explanation:

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16-7x

7 0
3 years ago
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