The second leftover expression is not o(a+b). It is 6(a + b). I have attached the correct question to depict that.
Answer:
The equivalent expressions are;
8a + 2 and 6a + 6b
Step-by-step explanation:
The two leftover expressions are given as;
2(4x + 1) and 6(a + b)
In algebra, equivalent expressions are simply those expressions which when simplified, give the same resulting expression as the initial one.
Thus simply means expanding or collecting like times to make it clearer.
Now, in our question, like terms have already been collected. This means that to find an equivalent expression, we will just expand the bracket.
Thus;
2(4x + 1) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;
8x + 2
Similarly,
6(a + b) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;
6a + 6b
Thus;
The equivalent expressions are;
8a + 2 and 6a + 6b
Answer:

Step-by-step explanation:
Given


See attachment
Required
Find 
First, calculate 
--- angle on a straight line
So, we have:

Collect like terms


Next, calculate PQR

So, we have:

Collect like terms


So, PRO is calculated as:
--- angles in a triangle
So, we have:


Collect like terms


Y=5
Step By Step:
180-75-75
30
4y+10=30
4y=20
y=5
Since this is an isosceles, you know that angle B is congruent to angle C (they’re both 75°).
Answer:
C. 8√3
Step-by-step explanation:
* = multiply or times
To find √192 in its simplest form we need to divide it by a square number like 64.
192/64 = 3
√192 = √64 * √3 = 8√3
4y/3 - 3/4 + 5/6y (multiply by) x 2 + 4
4y/3 - 3/4 + 5y/3 + 4
collect like terms: (4y/3 + 5y/3) + ( - 3/4 + 4)
simplify: 3y + 13/4 <----- FINAL ANSWER