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3 years ago

123,10kg to the nearest kg

Mathematics

2 answers:

DENIUS [597]3 years ago

8 0

Answer:123,000

Step-by-step explanation:

Eduardwww [97]3 years ago

8 0

123,10kg isn’t it? Right?

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What is the value of x in the triangle? A) 289 B) 17 C) 15 D) 14.2

kifflom [539]

For this you would use Pythagorean theorem (a^2+b^2=c^2) a=15 and c=sqrt 514 plug the numbers in and you’ll be set

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3 years ago

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List below are the speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, CA. Use the sample data to construct

zheka24 [161]

Answer:

The 99% confidence interval of the population standard deviation is 1.7047 < σ < 7.485

Step-by-step explanation:

Confidence interval of standard deviation is given as follows;

$\sqrt{\dfrac{\left (n-1 \right )s^{2}}{\chi _{1-\alpha /2}^{}}}< \sigma < \sqrt{\dfrac{\left (n-1 \right )s^{2}}{\chi _{\alpha /2}^{}}}$

s = $\sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }$

Where:

$\bar x$ = Sample mean

s = Sample standard deviation

n = Sample size = 7

χ = Chi squared value at the given confidence level

$\bar x$ = ∑x/n = (62 + 58 + 58 + 56 + 60 +53 + 58)/7 = 57.857

The sample standard deviation s = $\sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }$ = 2.854

The test statistic, derived through computation, = ±3.707

Which gives;

$C. I. = 57.857 \pm 3.707 \times \dfrac{2.854}{\sqrt{7} }$

$\sqrt{\dfrac{\left (7-1 \right )2.854^{2}}{16.812}^{}}}< \sigma < \sqrt{\dfrac{\left (7-1 \right )2.854^{2}}{0.872}}$

1.7047 < σ < 7.485

The 99% confidence interval of the population standard deviation = 1.7047 < σ < 7.485.

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3 years ago

Sunhee had four plastic shapes a square, a circle, and a pentagon in how many ways can she line up the four shapes of the circle

julsineya [31]

Answer:

only three shapes are mentioned.

But anyhow, 4 shapes allow the following reasoning...

you can start lining up with any of the for shapes, so you have 4 possibilities, for the second position you have 3 possibilities, for the third 2 and for the last only 1.

so 4*3*2*1= 24 possible ways

but with the added rule to keep the circle and the square apart, we have to reduce the number.

by the same step-by-step reasoning we get

4 possibilities for the 1st item

only 2 possibilities for the 2nd item

(if 1st is square or circle, the other one's not an option, if it's not we have to choose one of them to not place them both at point 3 and 4)

only 1 choice for the 3rd item

(reasoning as above, if 2nd is square or circle, we have to the only other, if it isn't, we can put it here at 3rd position)

plus scenarios where either square or circle are on 1st point, the other's on 4th.

I guess that makes 14 possible arrangements

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3 years ago

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marusya05 [52]

U didn’t give us enough info. We need the radius and then we can find the volume

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3 years ago

A(0,2), B(2,4), C(4,2), D(2,0) FIND THE SLOPE OF AC.

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Y= 4x
I think that’s the answer

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3 years ago

123,10kg to the nearest kg​

123,10kg to the nearest kg