Its a prime number the factor of it are 1,2,4,19,38,76,152.
6/5<13/10
6/5=120/100
6/5>11/10
(6/5 =12/10)
Given:
μ = $3.26 million, averaged salary
σ = $1.2 million, standard deviation
n = 100, sample size.
Let x = random test value
We want to determine P(x>4).
Calculate z-score.
z = (x - μ)/ (σ/√n) = (4 - 3.26)/(1.2/10) = 6.1667
From standard tables,
P(z<6.1667) = 1
The area under the distribution curve = 1.
Therefore
P(z>6.1667) = 1 - P(z<=6.1667) = 1 - 1 = 0
Answer: The probability is 0.
Answer: 0.0885
Step-by-step explanation:
Given : According to a recent Catalyst Census, 16% of executive officers were women with companies that have company headquarters in the Midwest.
i.e. p= 0.16
Sample size : n= 154
Now, the probability that more than 20% of this sample is comprised of female employees is given by :-

[∵
]
[Using the standard z-value table]
Hence, the required probability = 0.0885
Step-by-step explanation:
