Answer:
if(revenue.cents - expenses.cents < 0){
profit.dollars = revenue.dollars - expenses.dollars - 1;
profit.cents = 1 - revenue.cents - expenses.cents;
}
else{
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
}
Explanation:
We know that profit is given as: revenue - expenses from the question.
From the given expression above;
if(revenue.cents - expenses.cents < 0)
then profit.dollar will be revenue.dollars - expenses.dollars - 1; the 1 is to be carry over to the cent part. And the profit.cent will be 1 - revenue.cents - expenses.cents;
else the profit.dollars and the profit.cent is computed directly without needing to carry over:
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
Answer:
1 35
Explanation:
* There is a little typo in printf. It should be "\n".
Initially, the value of the first is 1, and the value of the second is 2. Then, do_something(&second, first) is called. The value of the <em>first</em> will still be 1. However, there is a call by reference for <em>second </em>variable. That means the change made by the function <em>do_something</em> will affect the value of the <em>second</em> variable.
When you look at the calculation inside the <em>do_something</em> function, you may see that value of the <em>second</em> will be 35.
I would evaluate baggage and personal belongings, rooms or closets, people's clothing, and if anyone has a weapon.
Answer:
B
Explanation:
we are in a digital generation, where by technology is gradually taking over the world. Almost all business, schools, company, etc make use of computer.
Answer:
A. Connectivity
Explanation:
I just answered this question.
