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baherus [9]
3 years ago
11

What type of maintenance can prevent the computer from breaking?

Computers and Technology
2 answers:
qwelly [4]3 years ago
3 0
<span>The answer is, "Load anti-virus software".
</span>Anti-virus softwares are used to prevent computer from virus, as it name shows that are anti-virus means they prevent from virus. Anti virus softwares are also known as anti-malware software. These software work in such a way that they <span>prevent, detect and then remove viruses or </span><span>malicious software.</span>
laila [671]3 years ago
3 0
The correct answer would be load a<span>nti-virus software.</span>
You might be interested in
Which two computer peripherals are connected to the computer through a port?
chubhunter [2.5K]
Most computer devices are connected to the computer through port
Keyboard through usb port
Printer through usb port
Hand point device through usb port
Also computer equipped with LPT port for printers and COM port for additional devices like external modems e.t.c
7 0
3 years ago
5.17 (Calculating Sales) An online retailer sells five products whose retail prices are as follows: Product 1, $2.98; product 2,
Dima020 [189]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

   

    //Initialize the prices as constants

    final double PRODUCT_1_PRICE = 2.98;

    final double PRODUCT_2_PRICE = 4.50;

    final double PRODUCT_3_PRICE = 9.98;

    final double PRODUCT_4_PRICE = 4.49;

    final double PRODUCT_5_PRICE = 6.87;

   

    //Declare the other variables

    int productNumber, quantitySold;

    double total = 0.0;

   

    //Create a Scanner object to get input

    Scanner input = new Scanner(System.in);

   

    //Create a while loop

    while(true){

        //Ask the user to enter the productNumber

     System.out.print("Enter the product number or 999 to quit: ");

     productNumber = input.nextInt();

     

     // Stop the loop, if productNumber is 999(sentinel value, you may choose any value you want)

     if(productNumber == 999)

         break;

     

     //Ask the user to enter the quantitySold

     System.out.print("Enter the quantity sold: ");

     quantitySold = input.nextInt();

     

     //Create a switch statement that works depending on the productNumber entered.

     //For example, if the productNumber is 1, it multiplies the quantitySold by PRODUCT_1_PRICE

     //   and adds the result to the total. If productNumber is 2, it does the same for product 2 ...

     switch(productNumber){

         case 1:

             total += quantitySold * PRODUCT_1_PRICE;

             break;

         case 2:

             total += quantitySold * PRODUCT_2_PRICE;

             break;

         case 3:

             total += quantitySold * PRODUCT_3_PRICE;

             break;

         case 4:

             total += quantitySold * PRODUCT_4_PRICE;

             break;

         case 5:

             total += quantitySold * PRODUCT_5_PRICE;

             break;

     }

    }

 

 //Print the total (when the loop is done)

 System.out.println("The total is $" + total);

}

}

Explanation:

*The code is in Java.

You may see the explanation as comments in the code.

4 0
3 years ago
Business customers pay $0.006 per gallon for the first 8000 gallons. If the usage is more than 8000 gallons, the rate will be $0
trasher [3.6K]

Answer:

#include <bits/stdc++.h>

using namespace std;

int main()

{

   // variables

   char cust_t;

   int no_gallon;

   double cost=0;

   cout<<"Enter the type of customer(B for business or R for residential):";

   // read the type of customer

   cin>>cust_t;

   // if type is business

   if(cust_t=='b'||cust_t=='B')

   {

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.006;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {

           // if number of gallons is greater than 8000

           // calculate cost

           cost=(8000*0.006)+((no_gallon-8000)*0.008);

           cout<<"total cost is: $"<<cost<<endl;

           

       }

       

   }

   

   // if customer type is residential

   else if(cust_t=='r'||cust_t=='R')

        {

           

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.007;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {// if number of gallons is greater than 8000

       // calculate cost

           cost=(8000*0.005)+((no_gallon-8000)*0.007);

           cout<<"total cost is: $"<<cost<<endl;      

       }        

   }

return 0;

}

Explanation:

Ask user to enter the type of customer and assign it to variable "cust_t". If the customer type is business then read the number of gallons from user and assign it to variable "no_gallon". Then calculate cost of gallons, if  gallons are less or equal to 800 then multiply it with 0.006.And if gallons are greater than 8000, cost for  first 8000 will be multiply by 0.006 and  for rest gallons multiply with 0.008.Similarly if customer type is residential then for first 8000 gallons cost will be multiply by 0.005 and for rest it will  multiply by 0.007. Then print the cost.

Output:

Enter the type of customer(B for business or R for residential):b                                                                                            

please enter the number of gallons:9000                                                                                                                      

total cost is: $56  

4 0
3 years ago
A Web site that allows users to enter text, such as a comment or a name, and then stores it and later display it to other users,
balandron [24]

Answer:

Option(c) is the correct answer.

Explanation:

Cross-site scripting is the type of security breach that are usually found in the  software applications.The main objective of cross site scripting it is used by the hackers to exploit the data security.

  • The cross site scripting is the collection of web pages  that enables people to insert the text like comment,  name stores it afterwards it save the data and then  it appears to the other users.
  • Others options are incorrect because they are not related to given scenario.
5 0
3 years ago
Read 2 more answers
Write the following function without using the C++ string class or any functions in the standard library, including strlen(). Yo
dolphi86 [110]

Answer:

The function in C++ is as follows

int chkInd(string str1, string str2){    

int lenstr1=0;

while(str1[lenstr1] != '\0'){  lenstr1++;  }

int index = 0; int retIndex=0;

for(int i=lenstr1-1;i>=0; i--){

   while (str2[index] != '\0'){

       if (str1[i] == str2[index]){

           retIndex=1;

           break;         }

       else{   retIndex=0;      }

  index++;    }

  if (retIndex == 0){   return i;   }else{return -1;}}

}

Explanation:

This defines the function

int chkInd(string str1, string str2){    

First, the length of str1 is initialized to 0

int lenstr1=0;

The following loop then calculates the length of str1

while(str1[lenstr1] != '\0'){  lenstr1++;  }

This initializes the current index and the returned index to 0

int index = 0; int retIndex=0;

This iterates through str1

for(int i=lenstr1-1;i>=0; i--){

This loop is repeated while there are characters in str2

   while (str2[index] != '\0'){

If current element of str2 and str1 are the same

       if (str1[i] == str2[index]){

Set the returned index to 1

           retIndex=1;

Then exit the loop

           break;         }

If otherwise, set the returned index to 0

       else{   retIndex=0;      }

Increase index by 1

  index++;    }

This returns the calculated returned index; if no matching is found, it returns -1

  if (retIndex == 0){   return i;   }else{return -1;}}

}

4 0
3 years ago
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