Question

Which expression is equivalent to log12 (1/2/8w)

Answer 1

Answer:

$log_{12}(\frac{1}{2} )-(log_{12}(8 )+log_{12}(w))$.

Step-by-step explanation:

The given logarithmic expression is $log_{12}(\frac{\frac{1}{2} }{8w})$.

We need to apply the quotient rule of logarithm, which is given as follows;

$log_{a}(\frac{M}{N} )=log_{a}(M )-log_{a}(N )$.

We apply this property to obtain,

$log_{12}(\frac{\frac{1}{2} }{8w})=log_{12}(\frac{1}{2} )-log_{12}(8w )$.

We again apply the product rule which is given as;

$log_{a}({M\times N)=log_{a}(M )+log_{a}(N )$.

We apply this rule to the last term to get,

$log_{12}(\frac{\frac{1}{2} }{8w})=log_{12}(\frac{1}{2} )-(log_{12}(8 )+log_{12}(w))$.

Therefore, the correct answer is B.

Answer 2

Answer:B

Step-by-step explanation: