Answer:
B)Oy+ 3 = 4(x - 1)
Equation of the straight line y +3 = 4( x-1)
Step-by-step explanation:
<u><em>Explanation:-</em></u>
<u><em>Step(i):-</em></u>
Given that the equation y = 4x +2
and given that the point (1,-3)
The equation of the parallel line to the given line
ax +by +k=0
4x-y +k=0
This line is passing through the point (1,-3)
⇒ 4(1) -(-3) +k=0
⇒ 4+3 +k=0
7 +k=0
k =-7
The equation of the Parallel line 4x-y -7 = 0
<u><em>Step(ii):-</em></u>
Given that the slope m = 4 and the point (1,-3)
Equation of the straight line
y - y₁ = m(x-x₁)
y -(-3) = 4( x-1)
y +3 = 4( x-1)
5/6, 1/3 hope this helps :))
Answer:
9 squares
Step-by-step explanation:
