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3 years ago

7

On a coordinate grid, plot the points (-2,4) and (-2,0). Join them with a line

1 answer:

KATRIN_1 [288]3 years ago

6 0

Answer:

a 4

Step-by-step explanation:

4x5=15jddjshshhshsjsjsjsjsjejejsjejejeejjssjsj

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What is the interquartile range

motikmotik

<em>Answer:</em>

<em></em>

<em>Step-by-step explanation:</em>

<em>Khan academy huh?</em>

<em>put the numbers in order from least to greatest.</em>
<em>find the median</em>
<em>find the difference between the median and all of the other numbers.</em>

<em></em>

<em></em>

<em>P.S. If you were looking for somebody to tell you the answer don't hold your breath.</em>

8 0

3 years ago

The difference between number 20 and its opposite is what percentage of 200? (if you do not remember: opposite of 15 is −15; opp

True [87]

20%

This is because 20 and it's opposite -20 is 40. (20 - -20 = 40). Then 40 is 20% of 200.

8 0

3 years ago

Read 2 more answers

A person borrows $10,000 and repays the loan at the rate of $2,400 per year. The lender charges interest of 10% per year. Assumi

omeli [17]

Answer:

a) $M(t)=24000-14000e^{t/10}$

b) It takes 5.390 years to pay off the loan.

Step-by-step explanation:

(a) The differential equation for the variation in the amount of the loan M is

$\frac{dM}{dt}=0.1M-2400$

We can express this equation as:

$\frac{dM}{dt}=0.1M-2400\\\\10\int \frac{dM}{M-24000} =\int dt\\\\10ln(M-24000)=t\\\\M-24000=Ce^{t/10}\\\\M=Ce^{t/10}+24000\\\\M(0)=Ce^{0/10}+24000=10000\\\\C+24000=10000\\\\C=-14000\\\\M(t)=24000-14000e^{t/10}$

(b) We can calculate this as M(t)=0

$M(t)=24000-14000e^{t/10}=0\\\\e^{t/10}=24000/14000=1.714\\\\t=10ln(1.714)=10* 0.5390=5.390$

It takes 5.390 years to pay off the loan.

8 0

3 years ago

Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method

antoniya [11.8K]

Answer:

a

The estimate is $- 0.0265\le K \le 0.0465$

b

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

The number of microchips broken in method B is $n_2 = 400$

The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

$p_1 = \frac{32}{400}$

$p_1 = 0.08$

The proportion of the faulty to the total breaks in method B is

$p_2 = \frac{28}{400}$

$p_2 = 0.07$

For this estimation the standard error is

$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

substituting values

$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

$SE = 0.0186$

The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

substituting values

$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

$K = - 0.0265 \ or \ K = 0.0465$

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

$- 0.0265\le K \le 0.0465$

3 0

3 years ago

Lucy took out a $15,000 to buy her new car. The bank charged her 8% simple interest rate for the term of 5 years. What is the en

MA_775_DIABLO [31]

Answer:

<h2>$21000</h2>

Step-by-step explanation:

This problem is on simple interest calcultion

A=P(1+r*n)

where

A=accumulated amount (final)

P= principal amount (initial), $15,000

r=interest written as decimal, 8% = 8/100= 0.08

n=number of years, 5years

Substituting into the expression we have

A=15000(1+0.08*5)

A= 15000(1+0.4)

A=15000(1.4)

A=$21000

<h2>Hence the ending balance that lucy would pay is $21000</h2>

5 0

3 years ago