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Naya [18.7K]
3 years ago
7

On a coordinate grid, plot the points (-2,4) and (-2,0). Join them with a line

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
6 0

Answer:

a 4

Step-by-step explanation:

4x5=15jddjshshhshsjsjsjsjsjejejsjejejeejjssjsj

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D=125 + 80n models the amount of money (d) in the register after selling n tickets. How much money does she have in the register
Papessa [141]

Answer:

She has $125 in the register before selling any tickets.

Step-by-step explanation:

If the cost of each ticket is $80 then the equation would just be d=80n. However, by adding 125 without any coefficient, this would make our starting point 125 and not 0. Our starting point is how much money is in the register prior to selling anything.

5 0
3 years ago
Suppose you toss a quarter, a dime and a nickel. Find the sample for all the possible ways the three poins and (heads, tails)
Katarina [22]
The answer is 24 but i am not sure for the sample 

7 0
3 years ago
Rewrite the expression 2(x + 5) using the Distributive Property.​
ehidna [41]

Answer:

2x + 10

Step-by-step explanation:

To expand (using the distributive property) <u>multiply</u> the number outside the bracket i.e. in this case '2', with the <u>values inside the brackets</u>.

So multiply '2' and 'x' and '2' and 5' and add or subtract on basis of whether the second value is positive or negative.

So

2(x + 5)

= (2*x)+(2*5)

=2x+10

<em>extention note:</em> <u>be careful</u> when the symbol within the equation within the brackets is a subtraction because it implies that the second value would instead be a negative number and should be treated as such.

an example

2(x-5)

= (2*x)+(2*-5)

=2x -10

Anyhow, I hope this helped!

5 0
3 years ago
Consider g (x) = StartFraction 4 x + 9 Over x Superscript 6 Baseline + 1 EndFraction Which statement correctly uses limits to de
Nastasia [14]

To find the end behavior of a function, we find it's limits as x approaches infinity, getting the correct option as:

As x approaches plus-or-minus infinity = limit of StartFraction 4 Over x Superscript 5 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches 0.

Function:

The function given is:

g(x) = \frac{4x+9}{x^6+1}

Limit as x goes to infinity:

To find the limit of a function as x goes to infinity, we consider the term with the highest exponent in the numerator and in the denominator. So

\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{4x+9}{x^6+1} = \lim_{x \rightarrow \infty} \frac{4x}{x^6} = \lim_{x \rightarrow \infty} \frac{4}{x^5} = \frac{4}{\infty^5} = 0

The graphic of the function, given at the end of this answer, corroborates the answer.

Thus, the correct option is:

As x approaches plus-or-minus infinity = limit of StartFraction 4 Over x Superscript 5 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches 0.

For more on limits as x approaches infinity, you can check brainly.com/question/12207599.

7 0
3 years ago
Read 2 more answers
How does the graph of g(x) = (x + 4)3 − 5 compare to the parent function f(x) = x3
vodka [1.7K]

Transforming the function using f(x - h) shifts its graph h units to the right. Here, we have h = -4, so the graph exists shifted 4 units to the left.

<h3>What are transforming functions?</h3>

The transformations of functions describe how to graph a function that exists moving and how its shape exists being changed. There exist basically three kinds of function transformations: translation, dilation, and reflection.

Let f(x) = x³ be the original function.

When -5 exists added to the y-value, it moves the point on the graph down 5 units. Compared to f(x), g(x) exists 5 units down.

f(x) = (x + 4)³ - 5

= [x- (- 4) ]³ - 5 (shift 4 units in the negative x direction that exists 4 units left)

Transforming the function using f(x - h) shifts its graph h units to the right. Here, we have h = -4, so the graph exists shifted 4 units to the left.

To learn more about transforming functions refer to:

brainly.com/question/14261221

#SPJ9

6 0
2 years ago
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