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trasher [3.6K]
3 years ago
15

Write the equation of this line. A line that contains point (2, –2) and perpendicular to another line whose slope is –1.

Mathematics
2 answers:
Scilla [17]3 years ago
7 0

\text{Let}\\k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp k\iff m_1m_2=-1\\--------------------\\\text{We have}\\k:y=-1x+b_1\to m_1=-1\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff-1m_2=-1\quad|:(-1)\to m_2=1\\\\\text{Therefore}\ l:y=1x+b_2\to y=x+b_2\\\\\text{We know, the line}\ l\ \text{contains point (2, -2).}}\\\\\text{Substitute the coordinates to the equation of the line}\ l:\\\\-2=2+b_2\qquad|-2\\\\-4=b_2\to b_2=-4\\\\Answer:\ y=x-4

vodka [1.7K]3 years ago
6 0

Answer:


Step-by-step explanation:

Step One

Find the perpendicular to the line with a given slope of - 1

m1 * m2 = - 1            Let the given line have a slope of - 1. Call it m1

-1 * m2 = - 1              Divide both sides by -1

-1/-1 * m2 = -1/-1

m2 = 1

Step Two

Write what you have so far

y = 1 * x + b

y = x + b

Step Two

Solve the general equation for (2,-2)

y = x + b

x = 2

y = -2

-2 = 2 + b      Subtract 2 from both sides

-2 - 2 = b       switch and add

b= - 4

Answer

y = x -4





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4.5\,ft + \left[\left(152\,\frac{ft}{s} \right)\cdot \sin 52^{\circ} \right] \cdot t - \frac{1}{2}\cdot \left(32.174\,\frac{m}{s^{2}} \right) \cdot t^{2} = 0

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Crank

Answer:

388.5yd²

Step-by-step explanation:

We have Triangle TUV

In the question, we are given already

Angle U = 32°

Angle T = 38°

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Side t = 31yd

Side u = ?

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Step 1

We find the third angle = Angle V

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