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2 years ago

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to determine the number of trout in a lake a lake a conservationist catches 124 trout tag them and throws them back into the lak

e later 44 trout are called 11 of them are tagged how many trout would the conservationist expect to be in the lake

1 answer:

natali 33 [55]2 years ago

8 0

Answer: 25

Step-by-step explanation:

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Jill earn $15 per hour babysitting class a transportation fee of five dollars per job. Write a formula for E, Ji Jill earn $15 p

daser333 [38]

Since you know the amount of what she earns you would use the number 15 and you dont know how long she worked you would put "x" next to the 15. so you would have 15x and then put a plus 5 to show her transportation fee. so you would have the equation of 15x+5:) and instead of x use h to show hours because h=hours

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6 0

3 years ago

For problems 1-5, use the unit circle to calculate the given values.

OverLord2011 [107]

Answer:

1=120

2=30

3=150

4=240

5=300

Step-by-step explanation:

i used a calculator

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3 years ago

40% of a nurse 's time is spent dispensing medicine to patients. If 16 hours per a week is spent dispending medicine, how many h

GarryVolchara [31]

Answer:

40

Step-by-step explanation:

16/.4=40

7 0

2 years ago

In a recent study of 42 eighth graders, the mean number of hours per week that they watched television was 19.6. Assume the popu

olya-2409 [2.1K]

Answer:

$19.6-2.42\frac{5.8}{\sqrt{42}}=17.43$

$19.6+2.42\frac{5.8}{\sqrt{42}}=21.77$

And the best option for this case would be:

a. (17.5, 21.7)

Step-by-step explanation:

Information given

$\bar X= 19.6$ represent the sample mean

$\mu$ population mean

$\sigma= 5.8$ represent the population deviation

n=42 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom, given by:

$df=n-1=42-1=41$

Since the Confidence is 0.98 or 98%, the significance would be $\alpha=0.02$ and $\alpha/2 =0.1$ , and the critical value would be $t_{\alpha/2}=2.42$

Replacing we got:

$19.6-2.42\frac{5.8}{\sqrt{42}}=17.43$

$19.6+2.42\frac{5.8}{\sqrt{42}}=21.77$

And the best option for this case would be:

a. (17.5, 21.7)

8 0

3 years ago

I'm new to the app. Stumped on all of these

nekit [7.7K]

What are you stumped on?

3 0

3 years ago