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irakobra [83]
3 years ago
15

to determine the number of trout in a lake a lake a conservationist catches 124 trout tag them and throws them back into the lak

e later 44 trout are called 11 of them are tagged how many trout would the conservationist expect to be in the lake
Mathematics
1 answer:
natali 33 [55]3 years ago
8 0

Answer: 25

Step-by-step explanation:

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A city council has to use its resources to improve either the water supply or the drainage system. At which level is this decisi
Fynjy0 [20]

A city council has to use its resources to improve either the water supply or the drainage system. At which level is this decision made?


The asnswer is: Government

5 0
3 years ago
Y = (1/4)x^2 - (1/2)lnx..over the interval (1, 7e) ...what is the arc length ?
xenn [34]
So, f[x] = 1/4x^2 - 1/2Ln(x) 
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
6 0
3 years ago
Express 17.5m in dm,cm,dam,mm,hm,km
Len [333]

Answer:

17.5 metres

175 decimetres

1750 centimetres

17500 millimetres

1.75 decametres

0.175 hectometre

0.0175 kilometre

Hope it helps,

Pls mark as brainliest answer...

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A closed box with a square base is to have a volume of 13 comma 500 cm cubed. The material for the top and bottom of the box cos
andrezito [222]

Answer:

x  =  1,5 cm

h  =  6  cm

C(min) = 135 $

Step-by-step explanation:

Volume of the box is :

V(b)  = 13,5 cm³

Aea of the top is equal to area of the base,

Let call  " x " side of the base then as it is square area is A₁ = x²

Sides areas are 4 each one equal to x * h  (where h is the high of the box)

And volume of the box is   13,5 cm³  = x²*h

Then   h  =  13,5/x²

Side area is :  A₂ =  x* 13,5/x²

A(b)  = A₁  + A₂

Total area of the box as functon of x is:

A(x)  = 2*x²  + 4* 13,5 / x

And finally cost of the box is

C(x)  = 10*2*x²   +  2.50*4*13.5/x

C(x)  = 20*x²  +  135/x

Taking derivatives on both sides of the equation:

C´(x)  =  40*x   -  135*/x²

C´(x)  = 0     ⇒      40*x   -  135*/x² = 0    ⇒  40*x³ = 135

x³  = 3.375

x  = 1,5 cm

And   h  =  13,5/x²     ⇒   h  =  13,5/ (1,5)²

h = 6 cm

C(min)  = 20*x²  + 135/x

C(min)  = 45  +  90

C(min)  = 135 $

8 0
3 years ago
Can someone please answer this?
telo118 [61]
Yes i can answer this
8 0
3 years ago
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