Answer:
usub from where
Step-by-step explanation:
If you have at least as many equations as your have unknown variables, the 'system' is solvable (unless the equations are copies of eachother).
In this case, isolate one letter and plug it in the other. I'm going for the 2a in the bottom one (it doesn't matter)
2a - 4b = 12 => (divide by two and move the b's to the other side)
a = 6 + 2b. (plug this one into the top equation)
4(6+2b) + 6b = 10 => 24+8b+6b = 10 => 24 + 14b = 10 => 14b = -14 => b=-1
a = 6 + -2 = 4.
So a=4 and b=-1.
Answer:
infinite solution
Step-by-step explanation:
hello
we substitute b = 4a + 2 in the second expression
12a -3*(4a+2) = -6
<=> 12a -12a -6 = -6
<=> -6 = -6
which is always true
so there is infinite solution
hope this helps
