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Tomtit [17]
2 years ago
7

Write a quadratic equation with a double root of -5

Mathematics
2 answers:
Sophie [7]2 years ago
8 0

Answer:

x^2 =5

Step-by-step explanation:

ASHA 777 [7]2 years ago
4 0

Answer:

x² + 10x + 25 = 0

Step-by-step explanation:

Given that x = - 5 is a root then (x + 5) is a factor

Since it is a double root then (x + 5)² so equation is

(x + 5)² = 0 ← expand factor using FOIL

x² + 10x + 25 = 0

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Solve and graph the following inequality: 3(7x+17) > -19 + 14x
love history [14]

Answer:

Solving the inequality we get: \mathbf{x>-7}

Step-by-step explanation:

We need to solve and graph the inequality 3(7x+17) > -19 + 14x

Solving:

3(7x+17) > -19 + 14x

Step 1: Multiply  3 with terms inside the bracket

21x+51 > -19 + 14x

Step 2:Subtracting 51 on both sides

21x+51-51 > -19 + 14x-51\\21x>14x-70\\

Step 3: Subtract 14x on both sides

21x-14x>+14x-70-14x\\7x>-70

Step 4: Divide both sides by 7

\frac{7x}{7}>\frac{-70}{7}\\x>-10

Solving the inequality we get: \mathbf{x>-7}

The graph is attached in the figure below.

5 0
3 years ago
find three points that belong to the graph and use them to sketch the graph of the equation: y = 2 + x
iris [78.8K]

Answer:

I only figured out two points which is (0,2) (1,3)

Step-by-step explanation:

8 0
2 years ago
Suppose f(x) = = x. Find the graph of f(x - 2).
JulsSmile [24]

Answer:

the answer is graph 1

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Simplify negative 8 over 3 divided by negative 2 over 6..
zavuch27 [327]

-9/3 / -2/6

= -9/3*6/-2

=-54/-6

=9

7 0
3 years ago
Read 2 more answers
Please help me :)))))
svetoff [14.1K]
Part a)

Answer: 5*sqrt(2pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(50/pi)
r = sqrt(50)/sqrt(pi)
r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(50pi)/pi
r = sqrt(25*2pi)/pi
r = sqrt(25)*sqrt(2pi)/pi
r = 5*sqrt(2pi)/pi

Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"

============================================================

Part b)

Answer: 3*sqrt(3pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(27/pi)
r = sqrt(27)/sqrt(pi)
r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(27pi)/pi
r = sqrt(9*3pi)/pi
r = sqrt(9)*sqrt(3pi)/pi
r = 3*sqrt(3pi)/pi

Note: the same issue comes up as before in part a)

============================================================

Part c)

Answer: sqrt(19pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(19/pi)
r = sqrt(19)/sqrt(pi)
r = (sqrt(19)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(19pi)/pi
8 0
3 years ago
Read 2 more answers
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