Answer:
The angles of a parallelogram are 135°-45°-135°-45°
Step-by-step explanation:
we know that
In a parallelogram opposites angles are congruent and consecutive angles are supplementary
Remember that
The sum of a exterior angle and its interior angle is equal to 180 degrees
Let
x ----> the measure of one interior angle of parallelogram
y ----> the measure of the other interior angle of parallelogram
we have that
solve for x
<em>Find the measure of the other interior angle of parallelogram</em>
Remember that consecutive interior angles are supplementary
substitute the value of x
solve for y
therefore
The angles of a parallelogram are 135°-45°-135°-45°
Answer:
The magazine that cost $15.24 for 6 issues cost more by $0.60/60 cents.
Step-by-step explanation:
Since $15.24 is 6 issues each and you need to even out the issues add $15.24+$15.24 then you would get $30.48, because its 15.24 each 6 add them both and it would be 12 issues. And the first issue $29.88 for 12 issues is only $29.88 while the other is $30.48 so the one with 6 issues/the second cost more than the first.
60 cents more because 29.88+60=30.48.
There are several conditions where triangles can be proved similar:
AA - where two of the angles are same.
SAS - where two sides of a triangle compare to the corresponding sides in the other are in same proportion, and the angle in the middle are equal.
SSS - Where all sides in a triangle and the corresponding sides are in the same proportion.
In the case above, we can only use the method of SAS, as only two sides of the triangles are given.
<HMG = <JMK (vertically opposite angles)
HM/MK = 8/12 = 2/3
GM/MJ = 6/9 = 2/3
As the two sides of a triangle comparing to the corresponding sides in the other are in same proportion, and the angle in the middle are equal, the above triangles are similar, with the prove of SAS.
Therefore, the answer is C.yes by SAS.
Hope it helps!
Answer:
UV=29
Step-by-step explanation:
In right triangles AQB and AVB,
∠AQB = ∠AVB ...(i) {Right angles}
∠QBA = ∠VBA ...(ii) {Given that they are equal}
We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle
∠AQB+∠QBA+∠BAQ=180 ...(iii)
∠AVB+∠VBA+∠BAV=180 ...(iv)
using (iii) and (iv)
∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV
∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV (using (i) and (ii))
∠BAQ=∠BAV...(v)
Now consider triangles AQB and AVB;
∠BAQ=∠BAV {from (v)}
∠QBA = ∠VBA {from (ii)}
AB=AB {common side}
So using ASA, triangles AQB and AVB are congruent.
We know that corresponding sides of congruent triangles are equal.
Hence
AQ=AV
5x+9=7x+1
9-1=7x-5x
8=2x
divide both sides by 2
4=x
Now plug value of x=4 into UV=7x+1
UV=7*4+1=28+1=29
<u>Hence UV=29 is final answer.</u>
Answer:
32×(-8.1)=-259.2
Step-by-step explanation:
