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3 years ago

Jim has ten more dollars than gail. together the have 27 dollars how much money does gail have

1 answer:

5 0

J = g + 10
j + g = 27

g + 10 + g = 27
2q + 10 = 27
2q = 27 - 10
2q = 17
g = 17/2
g = 8.50 <=== Gail has $ 8.50

j = g + 10
j = 8.50 + 10
j = 18.50....Jim has $ 18.50

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Tamisha ordered 4 pepperoni pizzas and 2 sausage pizzas for $60.50. Megan ordered 2 pepperoni pizzas and 3 sausage pizzas for $4

Ahat [919]

Answer: Look at picture

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3 years ago

How does the graph of y = sec(x + 3) – 7 compare with the graph of y = sec(x)?

Alla [95]

Answer:

The function y = sec(x) shifted 3 units left and 7 units down .

Step-by-step explanation:

Given the function: y = sec(x)

If k is any positive real number, then the graph of f(x) - k is the graph of y = f(x) shifted downward k units.

If p is a positive real number, then the graph of f(x+p) is the graph of y=f(x) shifted to the left p units.

The function $y = \sec(x+3)-7$ comes from the base function y= sec(x).

Since 3 is added added on the inside, this is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift down 7 units.

Therefore, the transformation on the given function is shifted 3 units left and 7 units down

3 0

3 years ago

Read 2 more answers

Please help this hurts

Svetllana [295]

Answer:

6x - 11y = -13 is the answer.

Step-by-step explanation:

Let's plug in the points to see what sticks.

Start with (-4, -1)

1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38 $\neq$ 13

2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13

3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17 $\neq$ 17

4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13 $\neq$ 13

The only one that fits is #2. Let's try the other point to be sure.

2) 6x - 11y = 6(1.5) - 11(2) = 9 - 22 = -13

3 0

3 years ago

X = ? y = ? 16 45 degrees

mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}$

For x, we will be using the Cosine Function:

$\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}$ $(16)Cosine(45^{\circ})\text{ = x}$ $(16)(\frac{1}{\sqrt[]{2}})\text{ = x}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = x}$

Therefore, x = 8√2.

For y, we will be using the Sine Function.

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}$ $\text{ (16)Sine }(45^{\circ})\text{ = y}$ $\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = y}$

Therefore, y = 8√2.

5 0

2 years ago

On section AB, whose length is 192 cm, take the point C so that AC: CB = 1: 3. The point D is taken on the AC section so that CD

jasenka [17]

Answer:

112 cm

Step-by-step explanation:

Given:

AB = 192 cm
AC : CB = 1 : 3
CD = BC/12
The distance between midpoints of AD and CB = x

Find the length of AC and CB:

AC + CB = AB
AC + 3AC = 192
4AC = 192
AC = 192/4
AC = 48 cm

Find CB:

CB = 3AC = 3*48 = 144 cm

Find the length of CD:

CD = BC/12 = 144/12 = 12 cm

Find the length of AD:

AD = AC - CD = 48 - 12 = 36 cm

Find the midpoint of AD:

m(AD) = 36/2 = 18 cm

Find the midpoint of CB:

m(CB) = AC + 1/2CB = 48 + 144/2 = 48 + 82 = 130 cm

Find the distance between the midpoints:

x = 130 - 18 = 112 cm

4 0

3 years ago