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Nookie1986 [14]
3 years ago
15

PLEASE PLEASE HELP (DUE ASAP)! I was struggling a lot with this and I was hoping for an accurate answer! Name the correct angle

using the given diagram

Mathematics
1 answer:
uranmaximum [27]3 years ago
4 0

Answer:

Alright Ima jsut say common phrases and do em at the end

Veritcal angles:

Well these angles are equal and always across form each other. Too determine if its a vertical angle, if you see an “x” Like shape, you can draw a maximum of two lines, one horizontal, one vertical. The number those lines tough are vertical the fore the SAME.

Complementary angles:

These are 2 or more angles that add up to 90 degrees. You can have like 20 different angles with different numbers, as long as they add up to 90 degrees. 90 degrees is a right angle so no matter what, it has to equal 90 degrees from all angles.

Supplementary angles:

These are 2 or more angles that add up to 180 degrees or a straight line more common. As long as all the angles add up to 180, its supplementary.

Adjacent angles:

These are angle show lie next to each other. They don’t have anything special, their just next to each other. Ima use an example form the graph. Take for example the angle RNX. XNE is adjacent, its lies right next to it. Another Example could be KND. DNE is adjacent, right next to it.

1) ANR

2) KNE

3) KND

4) RNX

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Answer:

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36(x + 4) = 36

Divide both sides by 36

x + 4 = 1

Subtraact 4 from both sides

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Which statement accurately describes how to perform a 90° clockwise rotation of point A (1,4) around the origin?
pochemuha

Answer:

B)Create a circle with the origin as its center and a radius of the origin and point A, then locate a point on the circle that is 90  clockwise

Step-by-step explanation:

This is because, to locate a point rotated by 90° from point A, we first draw a circle with the origin as its center and a radius of the origin and point A. We then locate a point on the line that is 90° clockwise from point A. For a 90° clockwise rotation, for a given pair of coordinates, (x,y), the resulting pair of coordinates is (y,-x). So, for the coordinates (1,4), the resulting coordinates we are looking for is (4, -1), which is the point rotated 90° clockwise from point A. The point is thus (4,-1).

3 0
4 years ago
Prove that the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus.
sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

  1. All the sides of the rhombus are congruent:  |DG|\cong |GF| \cong |EF| \cong |DE|
  2. The diagonals are perpendicular

Using the distance formula; d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}

\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}

|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}

\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}

|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}

\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}

|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}

\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}

Using the slope formula; m=\frac{y_2-y_1}{x_2-x_1}

The slope of EG is m_{EG}=\frac{2c-0}{0-0}

\implies m_{EG}=\frac{2c}{0}

The slope of EG is undefined hence it is a vertical line.

The slope of  DF is m_{DF}=\frac{c-c}{a+b-(-a-b)}

\implies m_{DF}=\frac{0}{2a+2b)}=0

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since |DG|\cong |GF| \cong |EF| \cong |DE| and DF \perp FG , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is m_{DE}=\frac{2c-c}{0-(-a-b)}

m_{DE}=\frac{c}{a+b)}

The slope of FG is m_{FG}=\frac{c-0}{a+b-0}

\implies m_{FG}=\frac{c}{a+b}

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