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3 years ago

Plz answer picture included

Mathematics

2 answers:

fgiga [73]3 years ago

7 0

Answer:

Step-by-step explanation:

also close ur tabs bro, u will lag ur computer that way

Sedbober [7]3 years ago

6 0

Answer:

holy sh- thats alot brainly tabs

Step-by-step explanation:

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PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

m_a_m_a [10]

Answer:

d 20.4 years

Step-by-step explanation:

The equation is

A = Pe ^(rt)

We know that r = .034

We want the money to double so A = 2P

Substitute in

2P = P e ^(.034t)

Divide by P

2P/P = P/P e ^(.034t)

2 = e^ (.034t)

Take the natural log on each side

ln (2) = ln(e^ (.034t))

ln (2) = .034t

Divide by .034

ln (2) /.034 = .034t/.034

ln (2)/.034 = t

20.3867 =t

4 0

3 years ago

Which equation can be used to check whether 1/8 divided 6= 1/48?

S_A_V [24]

Answer:

Step-by-step explanation:

8 x 6 = 48 because you just add a 1

4 0

2 years ago

Read 2 more answers

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0

2 years ago

Explain how you could calculate the surface area of a<br> square pyramid.

lesya [120]

To find the surface area, use this square pyramid surface area formula: Square Pyramid Surface Area = 2 x B x S + B 2 B = Width of the Square Base S = Slant length of one of the triangular faces and is calculated from the height and base width by using the equation: S= The square root of [(.5B) 2 + Height 2] .

8 0

2 years ago

Read 2 more answers

In the figure YAZ = BAC by angle side angle which angles are congruent by CPCTC

Gelneren [198K]

Answer:

Step-by-step explanation

3 0

3 years ago