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Orlov [11]
3 years ago
12

There is a mistake in the following problem that Joe Schmoe solved. Rework the problem correctly. Explain what mistakes he had,a

nd what he should have done. 8x-27-10-6x = 15
Mathematics
1 answer:
Ber [7]3 years ago
3 0
That's just an equation where x=26
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Four students are running for class president: liz, sam, sue, and tom. the probabilities of sam, sue, and tom winning are 7⁄25 ,
Natali5045456 [20]
First, we need to convert all the fractions to have the same denominator. 10 and 25 are both multiples of 100, so 100 would be appropriate. 

Sam has a 7/25 chance. Because we want ?/100, something needs to change. To get from 25 to 100, you need to times 25 by 4, right? So, do the same with the 7.
7 x 4 = 28. Therefore Sam has a 28/100 chance.

Sue has 3/10. Using the same method, we can see that 3 needs to be multiplied by 10 (because 10 times 10 = 100). So Sue has a 30/100 chance.

Tom is already in the fraction we like, so just keep this as 21/100. 

Now, add 28/100, 30/100 and 21/100 to get 79/100. 

Because won of them will get the role of class president, we know that the probability adds to 1. To get a full probability (100/100, or 1), what needs to be added to 79/100? 

Another way of going about this is 100/100-79/100. The answer is 21/100

The probability of Liz winning is 21/100. 

Let me know if this is still unclear, I would be more than happy to explain in more detail if necessary :) 
8 0
3 years ago
The equation y equals x + 11 represents the length Y in centimeters of a snake X
rjkz [21]
Umm, what do you need me to answer? how long X is?

8 0
3 years ago
Solve for x : 7x-8a = 3x+24a
Bingel [31]

Answer:

4x=32a

Step-by-step explanation:

7 0
3 years ago
Does the number 404,500 have 6 significant figures?
Anestetic [448]

Answer:

It has 4 significant figures, not 6

Step-by-step explanation:

4045 are the significant figures here

6 0
3 years ago
Read 2 more answers
What reasons justify a solution to a rational equation?
Licemer1 [7]

Answer:

<em><u>A rational equation is an equation containing at least one fraction whose numerator and denominator are polynomials, ... These fractions may be on one or both sides of the equation. A common way to solve these equations is to reduce the fractions to a common denominator and then solve the equality of the numerators.</u></em>

Step-by-step explanation:

<h3><em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>t</u></em><em><u> </u></em><em><u>w</u></em><em><u>o</u></em><em><u>r</u></em><em><u>k</u></em><em><u>s</u></em><em><u> </u></em><em><u>o</u></em><em><u>u</u></em><em><u>t</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em></h3>
4 0
3 years ago
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