1) $375
500 *.25= 125
500-125= 375
2) (5/8)* 32= 20 girls in class
(3/8)* 32= 12 BOYS in class
4) 19+42+X=87
62+X= 87 (add 19 and 42 together )
X=25 ( subtract 87 from 62)
The answer to this question is 25
Answer:
64
Step-by-step explanation:
First of all substitute the values to where ever you see their corresponding variables to make them multiply.
x = 9
y = 3
z = 2
so we get
8x as 8(9),
7z as 7(2)
2y as 2(3)
then the it's will be
8(9) - 7(2) + 2(3)
which is
72 - 14 + 6
finally we get
64
Answer is 10(2k+5)
-----------------------------------
Work Shown:
20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)
Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer
Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
The answer to your problem is 58/90