#25 is fairly simple. Plug in -4 and 3 into the equation, and the extraneous root will be the one that does not work.
Extraneous root in this case is positive four since +4≠-4
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</span>In this case it's negative 3, since -3≠3
#29 can be turned into a quadratic equation.
Square both sides to get
Then bring the 2x+3 to the other side, setting the quadratic equal to zero.
Factor to find that it's equivalent to
(x-3)(x+1)=0
Therefore x is equal to positive 3 and negative 1. Plug both back into the original equation. Whichever does not work is the extraneous root, and the answer is the one that does.
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</span>Extraneous root would be negative 3.
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</span>Extraneous root would be positive 1.
Your answers are positive 3 and negative 1.
Extraneous roots are negative 3 and positive 1.
Extraneous root in this case is positive four since +4≠-4
<span>
</span>In this case it's negative 3, since -3≠3
#29 can be turned into a quadratic equation.
Square both sides to get
Then bring the 2x+3 to the other side, setting the quadratic equal to zero.
Factor to find that it's equivalent to
(x-3)(x+1)=0
Therefore x is equal to positive 3 and negative 1. Plug both back into the original equation. Whichever does not work is the extraneous root, and the answer is the one that does.
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</span><span>
</span><span>
</span>Extraneous root would be negative 3.
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</span><span>
</span>Extraneous root would be positive 1.
Your answers are positive 3 and negative 1.
Extraneous roots are negative 3 and positive 1.
