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2 years ago

PLZ ANSWER NO FAKE LINKS AND DONT SAY I READY ISNT ALLOWED

Mathematics

2 answers:

natulia [17]2 years ago

5 0

Answer:

266

Step-by-step explanation:

285+127-146=266

Dmitrij [34]2 years ago

4 0

Answer:

A. 266

Step-by-step explanation:

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The volume of a cylinder is given by the formula <img src="https://tex.z-dn.net/?f=V%2B%20%5Cpi%20r%5E2h" id="TexFormula1" title

n200080 [17]

V = $\pi r^{2}h$ where r is radius and h is height

so when radius is (x+8) and height is (2x+3),

volume = $\pi (x+8)^{2}(2x+3)$

4 0

3 years ago

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Tell whether the ordered pair (- 3, 0) is a solution of the given system. - 2x + 2y >= 4an y >= 2x - 6

alukav5142 [94]

Answer:

The ordered pair is a solution.

Step-by-step explanation:

Plug x = -3 and y = 0 into the 2 inequalities and see if they fit:

-2x + 2y >= 4

-2(-3) + 2(0) = 6 which is > 4 so this one fits.

y>= 2x - 6

0 >= 2*-3) - 6 = -12 which also fits.

8 0

2 years ago

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the length of a rectangle is 9 units more than the width of the rectangle, w. if the width of the rectangle is more than 20 unit

Delvig [45]

Answer:

$W>20$

Step-by-step explanation:

Let

L-----> the length of a rectangle

W---> the width of a rectangle

we know that

$L=W+9$ -----> equation A

$W>20$ -----> inequality B

The inequality B represent the equation that could be used to find the possible values of the width

The solution for the width of the rectangle is all real numbers greater than 20 units

3 0

2 years ago

Exit

Zarrin [17]

Answer:

one third :) ;) hope it helps

5 0

3 years ago

Y=x+1 y=x^2-1 please help i don't understand

ololo11 [35]

ANSWER

The solution is

$(x=1,y=2),(x=2,y=3)$

EXPLANATION

We have

$y=x+1---(1)$

and

$y=x^2-1---(2)$

Let us substitute equation (1) in to equation (2). This gives us,

$x+1=x^2-1(2)$

We rewrite this as a quadratic equation as the highest degree is 2.

$x^2-x-1-1=0$

This implies that

$x^2-x-2=0$

we factor to obtain,

$x^2+x-2x-2=0$

$x(x-1)-2(x-1)=0$

$(x-1)(x-2)=0$

This means,

$(x-1)=0\:\: or\:\:(x-2)=0$

$x=1\:\: or\:\:x=2$

We substitute this values into any of the above equations, preferably equation (1)

When, $x=1$ , $y=1+1=2$

When, $x=2$ , $y=2+1=3$

The solution is

$(1,2),(2,3)$

8 0

3 years ago