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3 years ago

What’s the correct answer for this?

Mathematics

2 answers:

hichkok12 [17]3 years ago

5 0

Answer:

Step-by-step explanation:

Look at the shape closely observe the following the imaginary lines;

OC = OA , OB = OD {these is the raduis of the circle;

note also line CQ = CD { the perpendicular line bisects line CD in two equal halves;

Similarly ;

note also line AP= PB { the perpendicular line bisects line OP in two equal halves}

Hence;

OP is congruent to the OQ

In maths we say something is congruent when they are the same shape and have same angles but we are allowed to flip it's side.

Diano4ka-milaya [45]3 years ago

3 0

Answer:

Step-by-step explanation:

OP = OQ

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A rocket carrying fireworks is launched from a hill 60 feet above a lake. The rocket will fall into the lake after exploding at

castortr0y [4]

Answer:

Step-by-step explanation:

Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60

The velocity of the rocket at its maximum height is zero

v = dh/dt = -32t + 96t

At the maximum height, v = 0

0 = -32t + 96t

32t = 96

t = 96/32

t = 3secs

Substitute t = 3 into the modeled function to get the maximum height

h(3) = -16(3)^2 + 96(3) + 60

h(3) = -16(9)+ 288 + 60

h(3) = -144+ 288 + 60

h(3) = 144 + 60

h(3) = 204

Hence the maximum height reached by the rocket is 204m

Get the height after 2 secs

h(t) = -16t^2 + 96t + 60

when t = 2

h(2) = -16(2)^2 + 96(2) + 60

h(2) = -64+ 192+ 60

h(2) = -4 + 192

h(2) = 188m

Hence the height of the rocket after 2 secs is 188m

3 0

3 years ago

The graphs of f(x) and g(x) are shown below:

rosijanka [135]

<h2>Answer:</h2>

Option: C is the correct answer.

C.) x = −3.8, 3

<h2>Step-by-step explanation:</h2>

The function f(x) is given by:

$f(x)=x^2-x-12$

and the function g(x) is given by:

$g(x)=-1.8x-0.6$

Now, we are asked to find the solution of the equation:

$f(x)=g(x)$

i.e. we have to find the value of x such that both the functions are equal i.e.

$x^2-x-12=-1.8x-0.6\\\\i.e.\\\\x^2-x+1.8x-12+0.6=0\\\\i.e.\\\\x^2+0.8x-11.4=0\\\\i.e.\\\\10x^2+8x-114=0\\\\i.e.\\\\5x^2+4x-57=0$

Now, on solving the equation using the quadratic formula i.e. the solution of the equation:

$ax^2+bx+c=0$

is given by:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here we have:

$a=5,\ b=4\ and\ c=-57$

Hence, the solution is given by:

$x=\dfrac{-4\pm \sqrt{4^2-4\times 5\times (-57)}}{2\times 5}\\\\i.e.\\\\x=\dfrac{-4\pm \sqrt{16+1140}}{10}\\\\i.e.\\\\x=-3.8\ and\ x=3$

6 0

3 years ago

What would the answer be for this equation? 3a^3b^2x2a^2b^5

Wewaii [24]

9514 1404 393

Answer:

6a^5b^7

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)(a^c) = a^(b+c)

It looks like you want to simplify ...

$3a^3b^2\times 2a^2b^5=(3\cdot2)a^{3+2}b^{2+5}=\boxed{6a^5b^7}$

7 0

3 years ago

Read 2 more answers

The formula to convert °F to °C is C = (F – 32).<br><br>Convert 50°C to °F

Harman [31]

50*C x 9/5 + 32 = 122 *F

4 0

2 years ago

Read 2 more answers

Let v = −5 and w = 0.

sammy [17]

Answer:

Step-by-step explanation:

sorry if wrong

7 0

3 years ago