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VikaD [51]
3 years ago
13

Helppppp

Computers and Technology
1 answer:
ASHA 777 [7]3 years ago
7 0

Answer:

=IF(E4<=F4, “Reorder”,”No”)

Explanation:

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Answer:

A b output 0110111111001111

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2 years ago
What is true about super computers?
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Explanation:

Super Computer are expensive computer that are used to provide very quick results. Super computer are used in calculating complex mathematical calculations. Calculations such as weather forecast and Atomic energy research. Therefore Super Computer perform complex calculations rapidly.

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3 years ago
The merge and center
elena-s [515]

Answer:

True

Explanation:

Merge & Center is a feature in excel that combines multiple cells and centers the contents of the first cell. You can merge columns and rows too.

8 0
3 years ago
File Sales.java contains a Java program that prompts for and reads in the sales for each of 5 salespeople in a company. It then
myrzilka [38]

Answer:

import java.util.Scanner;

public class Sales

{

public static void main(String[] args) {

   

    int sum;

    Scanner input = new Scanner(System.in);

   

    System.out.print("Enter number of salespeople: ");

    int salespeople = input.nextInt();

    int[] sales = new int[salespeople];

       

    for (int i=0; i<sales.length; i++)

    {

     System.out.print("Enter sales for salesperson " + (i+1) + ": ");

     sales[i] = input.nextInt();

    }

    System.out.println("\nSalesperson   Sales");

    System.out.println("--------------------");

    sum = 0;

       int maxSale = sales[0];

       int minSale  = sales[0];

       int minId=1;

       int maxId=1;

    for (int i=0; i<sales.length; i++)

    {

               System.out.println("     " + (i+1) + "         " + sales[i]);

 sum += sales[i];

  if(maxSale < sales[i])

           {

               maxSale = sales[i];

               maxId = i+1;

           }

           if(minSale > sales[i])

           {

               minSale = sales[i];

               minId = i+1;

           }

   }

System.out.println("Total sales: " + sum);

       System.out.println("The average sale is: " + sum / salespeople );

       System.out.println("Salesperson "+ maxId + " had the highest sale with "+ maxSale + ".");

       System.out.println("Salesperson "+ minId + " had the lowest sale with "+ minSale + ".");

       

       int amount = 0;

       int counter = 0;

       System.out.print("Enter an amount: ");

       amount = input.nextInt();

       for (int i=0; i<sales.length; i++)

    {

     if(sales[i] > amount) {

         counter++;

         System.out.println("Salesperson "+ (i+1) + " exceeded given amount. (Number of sales: " + sales[i] +")");

     }

    }

       System.out.println("Number of salespeople exceeded given amount is: "+ counter);

}

}

Explanation:

- Ask the user for the number of salesperson

- According to entered number, create an array called sales to hold sale number for each person

- In the first for loop, assign the given sales numbers

-  In the second for loop, print all the sales people with sales, calculate the total sales. Also, find the minimum and maximum sales numbers with associated individuals.

- Print total, average, highest, and lowest sales.

- Ask user enter an amount

- In the third for loop, find the sales people who exceeded this amount.

- Print number of sales people who exceeded the amount.

8 0
3 years ago
1. Implement a method factorial(int n), that takes a number (int) and returns its factorial. Factorial of an integer is the prod
marysya [2.9K]

Answer:

import java.io.*;

import java.util.*;

public class Main

{

public static int factorial(int n){

if (n == 0)

return 1;    

else

return(n * factorial(n-1)); //recursively calling factorial function

}

public static void fibbonaci(int n)

{

if(n>0)

{

c=a+b; //next term in series

a=b;

b=c;

System.out.print(" "+c);    

fibbonaci(n-1); //recursively calling fibbonaci function

}

}

static int a=0,b=1,c;

  public static void main(String[] args) {

  int list_num,fact;

      List<Integer> num=Arrays.asList(1,3,5,7,9); //arraylist with 1,3,5,7,9

      for(Integer i:num) //for-each loop

      {    

      a=0;

      b=1;

      list_num=i.intValue();

      System.out.println("Fibbonaci series for "+list_num);

      System.out.print(a+" "+b);

      fibbonaci(list_num-2); //calling fibbonaci for values in list

      fact=factorial(list_num); //calling factorial for values in list

      System.out.println();

      System.out.println("Factorial for "+list_num+" is "+fact);

      System.out.println();

     

      }

  }

}

6 0
3 years ago
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