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VikaD [51]
3 years ago
13

Helppppp

Computers and Technology
1 answer:
ASHA 777 [7]3 years ago
7 0

Answer:

=IF(E4<=F4, “Reorder”,”No”)

Explanation:

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Select the correct answer.
Svetradugi [14.3K]

Answer:

C. Universal

Explanation:

7 0
3 years ago
Write a class Example() such that it has a method that gives the difference between the size of strings when the '-' (subtractio
Mariulka [41]

Answer:

class Example:

def __init__(self, val):

self.val = val

def __gt__(self, other):

return self.val > other.val

def __sub__(self,other):

return abs(len(self.val) - len(other.val))

def main():

obj1 = Example('this is a string')

obj2 = Example('this is another one')

print(obj1 > obj2)

print(obj1 - obj2)

main()

\color{red}\underline{Output:}

3 0
3 years ago
What is computer-aided design/computer-aided manufacturing (CAD/CAM)? a.A cultural trend that places value on an individual's ab
masha68 [24]

Answer:

C. RFID tag Systems are used to create the digital designs and then manufacture the products

7 0
4 years ago
Write a program which increments from 0 to 20 and display results in Decimal on the console 2-b) Modify above program to increme
SVEN [57.7K]

Answer:

<em>This program is written in C++</em>

<em>Comment are used to explain difficult lines</em>

<em>The first program that prints 0 to 20 (in decimal) starts here</em>

#include<iostream>

int main()

{

//Print From 0 to 20

for(int i = 0;i<21;i++)

{

 std::cout<<i<<'\n';

}

}

<em>The modified program to print 0 to 20 in hexadecimal starts here</em>

#include<iostream>

using namespace std;

int main()

{

//Declare variables to use in conversion;

int tempvar, i=1,remain;

//Declare a char array of length 50 to hold result

char result[50];

//Print 0

cout<<"0"<<endl;

// Iterate from 1 to 20

for(int digit = 1; digit<21; digit++)

{

//Start Conversion Process

//Initialize tempvar to digit (1 to 20)

tempvar = digit;

while(tempvar!=0)

{

//Divide tempvar by 16 and get remainder

remain = tempvar%16;

if(remain<10)

{

 result[i++]=remain + 48;

}

else

{

 result[i++] = remain + 55;

}

//Get new value of tempvar by dividing it by 16

tempvar/=16;

}

//Print result

for(int l=i-1;l>0;l--)

{

cout<<result[l];

}

i=1;

cout<<endl;  

}

return 0;

}

//The Program Ends Here

See Attachments for program 1 and 2; program 2 is the modified version of 1

Download cpp
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> cpp </span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> cpp </span>
3 0
3 years ago
Given a 13 bit address bus, how many unique addressed could be accessed? g
valina [46]
2^13 = 8192 addresses
8 0
3 years ago
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