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3 years ago

Which statement is true regarding the Quick Access toolbar?

Computers and Technology

2 answers:

ANEK [815]3 years ago

7 0

Answer:

All of the above statements are true

Explanation:

Quick access can achieve the aforementioned statements

I am Lyosha [343]3 years ago

5 0

Answer:

All the above statements are true.

Explanation:

Quick Access toolbar: It can be located at the top left-hand corner of the screen or above the ribbon in almost all office applications

it contains all those functionality that is used frequently.it can be customizable

It can contain functions that are independent

It can be modified to contain any function that you use frequently.

It can contain functions that are also in the ribbon.

It can be modified to contain any function that you use frequently.

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Tech A says that gasoline vapors are lighter than air, so inspection pits do not have a fire hazard like above ground hoists. Te

Elden [556K]

Answer:

Tech B is correct.

Explanation:

First, It is international best practice never to exceed the lifting capacity of any hoist. To do so would expose those involved to risks that may prove to be fatal.

Second, research has shown that gasoline vapors, as well as vapor from almost all other flammable or ignitable liquids or substances, are heavier than air.

More specifically, Gasoline produces flammable vapors that are heavier than air by 3 to 4 times. This means they can travel for great distances along the ground. Worst still, inspection pits are must be kept free from gas vapors because they tend to accumulate in low or enclosed spaces.

Both technicians should and must observe all occupational, health, and safety rules and guidelines stipulated and required for their industry/practice.

Cheers

4 0

2 years ago

Domain of (x+8)/(x(x+10))

UkoKoshka [18]

The domain of this, assuming it's a function, is all real numbers such that x does not equal zero or negative ten.

In interval notation, this is (-∞, -10) U (-10, 0) U (0, ∞).

In set builder notation, this is {x | x ≠ -10, x ≠ 0}.

These inputs are excluded from the domain because they would otherwise allow division by zero. Try plugging in one of the restricted inputs. You'll see that it does not work! On a graph of this function, you will see vertical asymptotes.

5 0

3 years ago

What kind of device is a printer? output or input

ANEK [815]

A printer is output. :)

8 0

2 years ago

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

To get an expression for one server

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

Hence, the smallest number of servers required is 3 servers

6 0

3 years ago

What form of note taking would be MOST beneficial for a visual learner who needs to see the connections between ideas?

Svetlanka [38]

Answer:

Think link

Explanation:

8 0

3 years ago