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Jet001 [13]
2 years ago
7

If you flip a coin and roll a 6-sided die, what is the probability that you will flip a tails and roll at least a 2?

Mathematics
1 answer:
Finger [1]2 years ago
4 0

Step-by-step explanation:

Flipping a tails and rolling at least a tail are 2 independent events: they don't affect each other. So, to get the probability of both happening, we just need to multiply the probability of one by the probability of the other. he probability of rolling at least a 2 is 5/6.

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How did you get to put a picture
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frutty [35]

The inverse function theorem says

\dfrac{\mathrm df^{-1}}{\mathrm dx}(16)=\dfrac1{\frac{\mathrm df}{\mathrm dx}(f^{-1}(16))}

We have

f(x)=x^2+4x-5

defined on x>-2, for which we get

f^{-1}(x)=-2+\sqrt{x+9}

and

f^{-1}(16)=-2+\sqrt{16+9}=3

The derivative of f(x) is

f'(x)=2x+4

So we end up with

\dfrac{\mathrm df^{-1}}{\mathrm dx}(16)=\dfrac1{\frac{\mathrm df}{\mathrm dx}(3)}=\dfrac1{10}

6 0
2 years ago
Solve this equation <br> 3/4(2x+5=14
Komok [63]
Hello there.

<span>Solve this equation 
3/4(2x+5=14

First, S</span><span>implify both sides

Next, </span><span>Subtract 15 over 4 from both sides.

Then, </span><span>Multiply both sides by 2 over 3

Final Answer: </span>x=41/6
5 0
3 years ago
Find the missing measure for a right circular cone given the following information. Find V if r = 2 and L.A. = 12. (16/3)√2 16√2
aksik [14]

Volume of cone is given by formula

V = \frac{\pi r^{2}h}{3}-------------------------------------------(1)

We are already given r =2, so we need to find h and then we can find volume

So missing meausre is height here ------------------------------------------------------------------------------

To find h we will use lateral area = 12\pi given

Formula for lateral area of cone is \pi r\sqrt{r^{2}+ h^{2}}

so we have12 = \pi r\sqrt{r^{2}+ h^{2}}

Now plug r as 2 in this equation

12 \pi = \pi (2)\sqrt{2^{2}+ h^{2}}

Now solve for h as shown and get h by itself

\frac{12\pi}{2\pi}  = \frac{2\pi\sqrt{4+h^{2}}}{2 \pi}

6  = \sqrt{4+h^{2}}

6^{2}   = \sqrt{4+h^{2}}  ^{2}

36}   = 4+h^{2}36 - 4    = 4+h^{2} -4

32  = h^{2}\sqrt{32} = \sqrt{h^{2}}

\sqrt{16 \times 2} = h\sqrt{16} \times \sqrt{2} = h

4\sqrt{2} = h----------------------------------------------------(2)

Now plug 2 in r place and 4\sqrt{2} in h place in volume formula given in (1)

V = \frac{\pi r^{2}h}{3}

V = \frac{\pi (2)^{2}4\sqrt{2}}{3}     [/tex][tex] V = \frac{\pi (4)4\sqrt{2}}{3}

V = \frac{16 \pi \sqrt{2}}{3}

so choice (1) is right answer

(1)  \frac{16 \sqrt{2}\pi}{3}

correct answer --------------------------------------------------------------------------------------------------

(2)  16 \sqrt{2} \pi

incorrect answer as correct volume answer we got as \frac{16 \sqrt{2}\pi}{3} --------------------------------------------------------------------------------------------------

(3)  4 \sqrt{38} \pi

incorrect answer as correct volume answer we got as \frac{16 \sqrt{2}\pi}{3} --------------------------------------------------------------------------------------------------------

6 0
3 years ago
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jenyasd209 [6]

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y = mx + b

y = -2x + 1

8 0
3 years ago
Read 2 more answers
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