A fire department's ladder is 110 feet long. A firefighter is trying to reach the top of a 100 foot building by leaning the ladd er against the building. What is the angle of elevation for the rescue ladder?
1 answer:
Answer:
sin-¹(10/11)
Step-by-step explanation:
The height of the building is 100 ft and the ladder is 110ft long .We can imagine this situation as a right angled ∆. For figure refer to the attachment .
We can use ratio sine here. Let the angle of elevation be theta.
<u>In </u><u>∆</u><u> </u><u>ABC </u><u>:</u><u>-</u><u> </u>
=> sinθ = p/h
=> sinθ = 100ft / 110 ft
=> sinθ = 10/11
= > θ = sin - ¹ ( 1 0 / 1 1 ) .
<h3><u>Hence </u><u>the</u><u> </u><u>angle</u><u> of</u><u> elevation</u><u> </u><u>is </u><u>sin </u><u>-</u><u>¹</u><u> </u><u>(</u><u> </u><u>1</u><u>0</u><u>/</u><u>1</u><u>1</u><u>)</u><u>. </u><u> </u></h3>
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