I think the answer is D because all the other options have a decimal point e.g. $4.46, (I don't use pounds but I'm assuming it's something like 4 pound 46), 4 hours, 46 minutes. You simply cannot have 0.46 of a dog (unless you're very cruel.)
N.B. I only used 4.46 as an example, it's not the correct number.
Answer:
That is the commutative property.
#1 Mrs. Garcia is making 50 snacks for her 5th grade class. If she uses four 1-kilogram bags of dried fruit, how many of grams of fruit will she use for each snack?
1 kilogram is equal to 1000 grams.
4 kilograms is equal to 4000 grams.
You would need to divide the 4000 total grams by the 50 snack to get how many grams would be in each snack.
So you would do..
4000grams/50snacks = 80 grams each snack.
#3 Toni's recipe also calls for seasonings. She needs to stir in 215 milligrams of pepper and 437 milligrams of salt. What is the difference between the total amount of seasonings and 1 gram?
215 milligrams is equal to 0.215 grams
437 milligrams is equal to 0.437 grams
So you would add these two together
0.215 + 0.437 = 0.652 grams
Then to find the difference you would subtract 0.652 grams from 1 gram
1 - 0.652 = 0.348
0.348 is the difference.
We want to find miles per hour.
Speed is distance over time.
So take 10 miles (distance) / 3 hours (time)
This is the same as 10/3.
10/3 = 3 and 1/3
Therefore, the girl is going 3 and 1/3 miles per hour.
Answer: (751.05, 766.95)
Step-by-step explanation:
We know that the confidence interval for population mean is given by :-
,
where
=population standard deviation.
= sample mean
n= sample size
z* = Two-tailed critical z-value.
Given : 
n= 42

We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576
Now, the 99% confidence interval around the true population mean viscosity :-
![759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)](https://tex.z-dn.net/?f=759%5Cpm%20%282.5760%29%5Cdfrac%7B20%7D%7B%5Csqrt%7B42%7D%7D%5C%5C%5C%5C%3D759%5Cpm%20%282.5760%29%283.086067%29%5C%5C%5C%5C%3D759%5Cpm7.9497%3D%28759-7.9497%2C%5C%20759%2B7.9497%29%5C%5D%5C%5C%3D%28751.0503%2C%5C%20766.9497%29%5Capprox%28751.05%2C%5C%20766.95%29)
∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)