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3 years ago

Can someone help please?

Mathematics

1 answer:

deff fn [24]3 years ago

8 0

Slope = 75
Y-intercept = 150

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Find the perimeter of the polygon ABCD that has its vertices at A(2, –2), B(6, –2), C(6, 6), and D(2, 6).

sergiy2304 [10]

Answer:

D. 24 Units

Step-by-step explanation:

tracing the points given we get a rectangle

the perimeter of a rectangle = 2a+2b

a=length

b= width

in this case a= 8

b= 4

the perimeter of a rectangle = (2*8)+(2*4)

the perimeter of a rectangle = 16+8

the perimeter of a rectangle = 24

7 0

2 years ago

Given that2025=<br><img src="https://tex.z-dn.net/?f=%20%7B3%7D%5E%7Bk%20%5Ctimes%20%7D%20%7B5%7D%5E%7Bt%7D%20" id="TexFormula1"

damaskus [11]

Answer:

k = 4, t = 2

Step-by-step explanation:

Express 2025 as a product of its prime factors

2025 = $3^{4}$ × 5², that is

$3^{4}$ × 5² = $3^{k}$ × $5^{t}$

Comparing exponents of same bases on both sides, gives

k = 4 and t = 2

8 0

3 years ago

The fraction 13/16 is closest to which benchmark?

Nikolay [14]

Answer:

♡ madeline here ♡

- 1 is your answer. ✿

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Step-by-step explanation:

4 0

3 years ago

(U...

Tresset [83]

Answer:

the 19th term of the arithmetic sequence is 73.

Step-by-step explanation:

Given:

The arithmetic sequence whose common difference is

$d=4$

And first term is

$a=1$

Find the 19th term of the arithmetic sequence

$n=19$

Now we know that,

$a_{n}=a+(n-1)d$

Put all the value in above AP.

$a_{19}= 1+(19-1)4$

$a_{19}= 1+18\times 4$

$a_{19}= 1+72$

$a_{19}= 73$

So, $19_{th}$ term of the sequence is 73.

3 0

3 years ago

Can you answer the question pls? If your right then i'll give brain :p

enyata [817]

Answer:

Should be A, D, E.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers