Can someone help please?

Can I get some help please?

mamaluj [8]

Answer:

1) 68

/ \

4 17

/\

2 2

68=2*2*17

2) 104

/ \

4 26

/\ /\

2 2 2 13

104=2*2*2*13

3) 78

/\

2 39

/\

3 13

78=2*3*13

4) 225

/\

9 25

/\ /\

3 3 5 5

225=3*3*5*5

Second Part:

1) 45

/\

3 15

/\

3 5

45=3*3*5

2) 70

/\

2 35

/\

5 7

70=2*5*7

3) 54

/\

9 6

/\ /\

3 3 2 3

54=3*3*2*3

4) 126

/\

3 42

/\

3 14

/\

7 2

126=3*3*7*2

3 0

2 years ago

What is the value of x angel in a pentagon if each interior angel is 117 , 100 , 105 and 115

RUDIKE [14]

Answer:

Step-by-step explanation:

Well first you have to find what the total amount of all the interior angles. In Oder to do that you count how many sides the shape has the subtract two from that number. Take the number you get from that and multiply it by 180. That number is total amount of all the interior angles including the angle x. Take the angles you do know and add them together. Take the number you get from that and subtract it from the total amount of all interior angles. The number you get from that is your answer. The answer to this problem is 103.

3 0

2 years ago

What is 881,635 ÷ 20 and remainder plaese

Sonbull [250]

Answer:

44,081 R 15

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Demetrius and Yosef are training for a race.

Lemur [1.5K]

Answer:

Yosef finished the mile in 9 minutes.

Distance = 1 mile

Demetrius' speed = 7.5 miles per hour

Demetrius' time = Distance/speed

= 8 minutes

Demetrius finished the mile first by taking 1 minute less than Yosef's finishing time.

8 0

2 years ago

The owner of a bike shop that produces custom built bike frames has determined that the demand equation for bike frames is given

o-na [289]

Answer:

equilibrium point (10,340)

Step-by-step explanation:

To find the equilibrium point, equal the demand and the supply:

$D(q)=S(q)\\\\-6.10q^2-5q+1000=3.2q^2+10q-80$

Reorganize the terms in one side and reduce similar terms:

$3.2q^2+6.1q^2+5q+10q-80-1000=0\\\\9.3q^2+15q-1080=0$

that's a cuadratic equation, solve with the general formula when:

a=9.3, b=15, c=-1080

$q_{1}=\frac{-b+\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{1}=\frac{-15+\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{1}=\frac{-15+201}{18.6}\\\\q_{1}=\frac{186}{18.6}\\\\q_1=10$

q can't be negative because it is the quantity of bike frames, so:

$q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-15-\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{2}=\frac{-15-201}{18.6}\\\\q_{2}=\frac{-216}{18.6}\\\\$

This value of q can't be considered.

Then substitute the value of q in D(q) to find the price p:

$D(10) = -6.10(10)^2-5(10) + 1000\\\\D(10)=340=p$

The equilibrium point (q,p) is (10,340).

6 0

2 years ago