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Kryger [21]
3 years ago
5

Solve the right triangle. round your answer to the nearest tenth​

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0

Answer:

?

Step-by-step explanation:

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(6.25•10^9)(9.8•10^16)
AVprozaik [17]

Answer:

This is your answer.. you add exponents

7 0
3 years ago
What is the answer A, B, C, or D
adell [148]

The answer would have to be

D


7 0
3 years ago
Find the exact value of csc theta if tan theta = sqrt3 and the terminal side of theta is in Quadrant III.
WARRIOR [948]

Answer:

3rd option

Step-by-step explanation:

Using the identities

cot x = \frac{1}{tanx}

csc² x = 1 + cot² x

Given

tanθ = \sqrt{3} , then cotθ = \frac{1}{\sqrt{3} }

csc²θ = 1 + (\frac{1}{\sqrt{3} } )² = 1 + \frac{1}{3} = \frac{4}{3}

cscθ = ± \sqrt{\frac{4}{3} } = ± \frac{2}{\sqrt{3} }

Since θ is in 3rd quadrant, then cscθ < 0

cscθ = - \frac{2}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } = - \frac{2\sqrt{3} }{3}

8 0
3 years ago
3х + 2y = 2<br> y = 4<br> Substitution
Pavel [41]

Answer:

x=-2

Step-by-step explanation:

hi! let's plug in 4 for y in the equation.

3x+2(4)=2

3x+8=2

3x=-6

x=-2

7 0
3 years ago
Read 2 more answers
What is this problem
Veronika [31]

The coordinate of the vertex is; (h, k) = (3, -5)

The final equation of the parabola is; y = 5(x - 3)² - 5

<h3>How to find the vertex of a Parabola?</h3>

The vertex is the coordinate of the crest or trough of the curve. Now, in the given graph, we only have a Trough which is the lowest point of the graph.

The coordinate of the vertex is; (h, k) = (3, -5)

2) Since the general equation is;

y = a(x - h)² + k

We will have;

y = a(x - 3)² - 5

At x = 2, y = 0. Thus;

0 = a(2 - 3)² - 5

a - 5 = 0

a = 5

3) The final equation of the parabola is;

y = 5(x - 3)² - 5

Read more about Parabola Vertex at; brainly.com/question/17987697

#SPJ1

3 0
1 year ago
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