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2 years ago

8

Prove

class="latex-formula">

2+2=5

2 answers:

irina1246 [14]2 years ago

5 0

jwjwhbahauiwbsbbdvwhwuusg

egoroff_w [7]2 years ago

5 0

Step-by-step explanation:

pahli baat toh ye photo guugle se lai hu aur dusri baat ye ki woh insan sacchi main genius hai jissne ye prove kiya aur kuch nahi┐( ˘_˘)┌

lyf goes on~•,•

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Is none proportional it proportional

Romashka-Z-Leto [24]

Answer:No it is not proportional

Step-by-step explanation:

The reason non proportional is not proportional is bc it's not proportional.

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3 years ago

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ivann1987 [24]

Answer:

Neither the scene nor the positions of the cameras are shown....

Without more detail of the problem, it would seem three different cameras would show the same scene only if they were all in exactly the same place, which is not possible.

Step-by-step explanation:

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3 years ago

What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?

ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

$d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}$

where

$(x_1,y_1)$ are the coordinates of the first point

$(x_2,y_2)$ are the coordinates of the second point

- For AB:

$d=\sqrt{[1-(-5)]^{2}+(4-4)^2}$

$d=\sqrt{(1+5)^{2}+(0)^2}$

$d=\sqrt{(6)^{2}}$

$d=6$

- For BC:

$d=\sqrt{(3-1)^{2} +(-4-4)^{2}}$

$d=\sqrt{(2)^{2} +(-8)^{2}}$

$d=\sqrt{4+64}$

$d=\sqrt{68}$

$d=8.24$

- For AC:

$d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}$

$d=\sqrt{(3+5)^{2} +(-8)^{2}}$

$d=\sqrt{(8)^{2} +64}$

$d=\sqrt{64+64}$

$d=\sqrt{128}$

$d=11.31$

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

$p=AB+BC+AC$

$p=6+8.24+11.31$

$p=25.55$

$p=25.6$

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

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3 years ago

Samantha drew Triangle JKL with the coordinates (2,3), (4, 3) and (5,2). She reflected this image over the x-axis to create an i

zavuch27 [327]

Answer:

J'(2,-3), K'(4, -3) and L'(5,-2)

Step-by-step explanation:

The given triangle has vertices at J(2,3), K(4, 3) and L(5,2).

The transformation rule for a reflection in the x-axis is:

$(x,y)\to (x,-y)$

We substitute the points to obtain the coordinates of the image triangle J'K'L'

$J(2,3)\to J'(2,-3)$

$K(4,3)\to K'(4,-3)$

$L(5,2)\to L'(5,-2)$

In other words, we negate the y-coordinates of triangle JKL to obtain the coordinates of J'K'L'

See attachment for graph.

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3 years ago

The length of a rectangle is 4 times its width. The perimeter of the rectangle is 50 cm long. What is the area of the rectangle?

Eduardwww [97]

The answer would be 100

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2 years ago