Answer:
Step-by-step explanation:
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Answer:
7π
Step-by-step explanation:
SO first find the area of the whole circle
which has a radius of 3
a=πr^2
So 3^2=9
9π
Now the two circles which are the same in area due to having the same radius
so if you plug in the 1 for radius the answer would just be π or 1π
now multiply that by 2 becuase there are 2 identical circles
π*2=2π
Now subtract
9π-2π=7π
Since they are just next to each other ill take it multiplication and that would be 128 if its not let me know and ill correct it
In this equation, you are solving for y. Simply isolate the variable by adding 1/4 to each side. The -1/4 and 1/4 will cancel out on the right side of the equation, leaving only y:
5/4 = y - 1/4
5/4 + 1/4 = y - 1/4 + 1/4
6/4 = y
y = 6/4
Don't forget to simplify y:
y = 3/2
Answer:
2097150
Step-by-step explanation:
<u>GIVEN :-</u>
- First term of G.P. = 6
- Forth term of G.P. = 384
<u>TO FIND :-</u>
- Sum of first 10 terms of the G.P.
<u>CONCEPT TO BE USED IN THIS QUESTION :-</u>
<em>Geometric Progression :-</em>
- It's a sequence in which the successive terms have same ratio.
- General form of a G.P. ⇒ a , ar , ar² , ar³ , ....... [where a = first term ; r = common ratio between successive terms]
- Sum of 'n' terms of a G.P. ⇒
.
<em>[NOTE :- </em>
can also be the<em> formula for "Sum of n terms of G.P." because if you put 'r' there (assuming r > 0) you'll get negative value in both the numerator & denominator from which the negative sign will get cancelled from the numerator & denominator. </em><em>YOU'LL BE GETTING THE SAME VALUE FROM BOTH THE FORMULAES.</em><em>]</em>
<u>SOLUTION :-</u>
Let the first term of the G.P. given in the question be 'a' and the common ratio between successive terms be 'r'.
⇒ a = 6
It's given that <u>forth term</u> is 384. So from "General form of G.P." , it can be stated that :-
Divide both the sides by 6.
![=> r = \sqrt[3]{64} = 4](https://tex.z-dn.net/?f=%3D%3E%20r%20%3D%20%5Csqrt%5B3%5D%7B64%7D%20%3D%204)
Sum of first 10 terms 
