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zimovet [89]
3 years ago
14

When dividing 592 by 9.25, how many zeros will be placed in the dividend?When dividing 592 by 9.25, how many zeros will be place

d in the dividend?
Mathematics
1 answer:
Ierofanga [76]3 years ago
3 0

Answer:

Step-by-step explanation:

9.25=\frac{925}{100} \\592 \div9.25=592 \div \frac{925}{100} =\frac{59200}{925}

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aniked [119]

Answer:

√{6854×6854}=√6854²=±6854 is your answer

3 0
3 years ago
Read 2 more answers
Wendell is looking over some data regarding the strength, measured in Pascals (Pa), of some building materials and how the stren
Slav-nsk [51]

The logarithmic model for the length when the strength is of 8 Pascals is given by:

  • f^{-1}(8) = \log_{2}{8} = \log_2{2^3} = 3
  • That is, the length is of 3 units.

<h3>What is the function?</h3>

The strength in Pascals for a building of length x is given by:

f(x) = 2^x

To find the length given the strength, we apply the inverse function, that is:

2^y = x

\log_{2}{2^y} = \log_2{x}

y = \log_2{x}

Hence, when the strength is of 8 Pascals, x = 8, and the length is given by:

f^{-1}(8) = \log_{2}{8} = \log_2{2^3} = 3

You can learn more about logarithmic functions at brainly.com/question/25537936

6 0
2 years ago
Jess says that two of the three points below are on a line through the origin.
Marrrta [24]

Answer:

(3, 8) and (9, 24) lie on the same line through the origin.

because (9, 24) is the result of dilatation of (3, 8) with scale factor 3.

(6, 21) is not the result, because 21 ≠ 2×8, even 6 = 2×3

6 0
3 years ago
Read 2 more answers
What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4
Alecsey [184]

Answer:  f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: f(x)=\dfrac{3x^2}{x^2-4}

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}

i.e. y=\dfrac{3}{1}=3

Hence, f(x) will have horizontal asymptote at y=3.

3 0
4 years ago
What’s the proof for this
KIM [24]
Well... Basically, you should prove this by SSS property(side-side-side). It's fair to say that the length of a side is equal to itself so The line that cuts through the rectangle is a side for both rectangles. Thus because of the given, all the sides of the triangles are equal to one another. This is a very important trick for geometry(I remember using it a lot).
Hope this helps!
7 0
3 years ago
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