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Evgesh-ka [11]
3 years ago
8

I need help pls !!!!!!

Mathematics
1 answer:
Rama09 [41]3 years ago
6 0

(k-7) would be the equation

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The vertices of a triangle are A(4, 1), B(9, 1), C(2, 5). What is the area of this triangle.
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Hey there!

\large\boxed{10u^2}

Formula for the area of a triangle is (1/2)bh.

Base of this triangle is 5, height is 4.

Image attached.

Plug values into the formula:

A = (1/2)(5)(4)

Simplify.

A = (1/2)(20)

A = 10

Area of the triangle is 10 units².

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$2, because if you do 8*25 you get 200 and if you divide that by 100 you get a total of 2 making the tax on the purchase $2.
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Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (
Vladimir79 [104]

Answer:

Factors: (x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0

Step-by-step explanation:

We are given a polynomial:

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We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0

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3 years ago
Changing 25/4 fraction into a mixed fraction
Veronika [31]
Divide 25 by 4 and you get 6 with a remainder of 1. That remainder of 1 can go over 4 to create the final answer of 6 and 1/4. 
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