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2 years ago

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Monthly budget- Total income 2910. 52 Mortgage 1100, childcare 682, Electric 200, phone 188, cable/tv 190. 76, food and grocerie

s 450,metro card 121. , pet supplies 90. , personal care 65, I have to prove my reasoning with what I know about fractions. Addition ,subtract of fractions. I need Help Felicia

1 answer:

diamong [38]2 years ago

8 0

Take 2910 and subtract 52-1100-682-200-188-190-76-450-121-90-65... you should get -304, i’m not sure what your question is asking, but if you take your income minus cost per month you should get your answer

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I need some help so if someone could help with shown work

murzikaleks [220]

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2 years ago

NewPop produces their brand of soda drinks in a factory where they claim that the

Citrus2011 [14]

Answer:

a) 14960 bottles

b) 502 bottles

Step-by-step explanation:

Given that:

Mean (μ) = 24 ounces, standard deviation (σ) = 0.14 ounces

a) From empirical rule (68−95−99.7%) , 68% of the population fall within 1 standard deviation of the mean (μ ± 1σ).

Therefore 68% fall within 0.14 ounces of the mean

the number of bottle = 22,000*68% = 14960 bottles

b) To solve this we are going to use the z score equation given as:

$z=\frac{x-\mu}{\sigma}$ where x is the raw score = 23.72

$z=\frac{x-\mu}{\sigma}=\frac{23.72-24}{0.14} =-2$

From the normal probability distribution table: P(X < 23.72) = P (Z < -2) = 0.0228

The number of rejected bottles = 22000 × 0.0228 = 502 bottles

8 0

3 years ago

12 divided by 4y+6 = 2/7

Mila [183]

Answer:

The correct answer is y = 9

Step-by-step explanation:

It is given that,

12/(4y + 6) = 2/7

<u>To find the value of y</u>

12/(4y + 6) = 2/7

By cross multiplying,

12 * 7 = 2 * (4y + 6 )

84 = 8y + 12

8y + 12 = 84

8y = 84 - 12

8y = 72

y = 72/8 = 9

y = 9

Therefore by solving the given expression we get the value of y = 9

3 0

3 years ago

Read 2 more answers

Find the critical points of the function f(x, y) = 8y2x − 8yx2 + 9xy. Determine whether they are local minima, local maxima, or

NARA [144]

Answer:

Saddle point: $(0,0)$

Local minimum: $(\frac{3}{8}, -\frac{3}{8})$

Local maxima: $(0,-\frac{9}{8})$ , $(\frac{9}{8},0)$

Step-by-step explanation:

The function is:

$f(x,y) = 8\cdot y^{2}\cdot x -8\cdot y\cdot x^{2} + 9\cdot x \cdot y$

The partial derivatives of the function are included below:

$\frac{\partial f}{\partial x} = 8\cdot y^{2}-16\cdot y\cdot x+9\cdot y$

$\frac{\partial f}{\partial x} = y \cdot (8\cdot y -16\cdot x + 9)$

$\frac{\partial f}{\partial y} = 16\cdot y \cdot x - 8 \cdot x^{2} + 9\cdot x$

$\frac{\partial f}{\partial y} = x \cdot (16\cdot y - 8\cdot x + 9)$

Local minima, local maxima and saddle points are determined by equalizing both partial derivatives to zero.

$y \cdot (8\cdot y -16\cdot x + 9) = 0$

$x \cdot (16\cdot y - 8\cdot x + 9) = 0$

It is quite evident that one point is (0,0). Another point is found by solving the following system of linear equations:

$\left \{ {{-16\cdot x + 8\cdot y=-9} \atop {-8\cdot x + 16\cdot y=-9}} \right.$

The solution of the system is (3/8, -3/8).

Let assume that y = 0, the nonlinear system is reduced to a sole expression:

$x\cdot (-8\cdot x + 9) = 0$

Another solution is (9/8,0).

Now, let consider that x = 0, the nonlinear system is now reduced to this:

$y\cdot (8\cdot y+9) = 0$

Another solution is (0, -9/8).

The next step is to determine whether point is a local maximum, a local minimum or a saddle point. The second derivative test:

$H = \frac{\partial^{2} f}{\partial x^{2}} \cdot \frac{\partial^{2} f}{\partial y^{2}} - \frac{\partial^{2} f}{\partial x \partial y}$

The second derivatives of the function are:

$\frac{\partial^{2} f}{\partial x^{2}} = 0$

$\frac{\partial^{2} f}{\partial y^{2}} = 0$

$\frac{\partial^{2} f}{\partial x \partial y} = 16\cdot y -16\cdot x + 9$

Then, the expression is simplified to this and each point is tested:

$H = -16\cdot y +16\cdot x -9$

S1: (0,0)

$H = -9$ (Saddle Point)

S2: (3/8,-3/8)

$H = 3$ (Local maximum or minimum)

S3: (9/8, 0)

$H = 9$ (Local maximum or minimum)

S4: (0, - 9/8)

$H = 9$ (Local maximum or minimum)

Unfortunately, the second derivative test associated with the function does offer an effective method to distinguish between local maximum and local minimums. A more direct approach is used to make a fair classification:

S2: (3/8,-3/8)

$f(\frac{3}{8} ,-\frac{3}{8} ) = - \frac{27}{64}$ (Local minimum)

S3: (9/8, 0)

$f(\frac{9}{8},0) = 0$ (Local maximum)

S4: (0, - 9/8)

$f(0,-\frac{9}{8} ) = 0$ (Local maximum)

Saddle point: $(0,0)$

Local minimum: $(\frac{3}{8}, -\frac{3}{8})$

Local maxima: $(0,-\frac{9}{8})$ , $(\frac{9}{8},0)$

4 0

3 years ago

Factor the expression. K^2-16h^2

Tresset [83]

Step-by-step explanation:

${k}^{2} - 16 {h}^{2} \\ \\ = {k}^{2} - (4 {h})^{2} \\ \\ = (k + 4h)(k - 4h)$

8 0

3 years ago