Describe the relationship between angles f, b, and a in the diagram.

A triangle has two sides of length 5 and 12. what value could the length of the third side be? More then one can be correct.

jeyben [28]

$Condition\ for\ existing\ triangle\\\\
a,b,c- sides\ of\ triangle\\\\
a+b>c\\a+c>b\\b+c>a\\
5+12=17\\\\
a)\ 712 \ , 7+12>5 \\
b)\ 512\\c)19\not5 \\\Third \side\ can\ be\ a,e,f
$

5 0

4 years ago

Drag the tiles to the correct boxes to complete the pairs. Find the distance between each pair of points. 5 units 4 units 2 unit

Olin [163]

Answer:

a) Distance between points A (5, 4) and B( 5, -2) is 6 units

b) Distance between points E (-2, -1) and F( -2, -5) is 4 units

c) Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) Distance between points G(3, -5) and H(6, -5) is 3 units

Step-by-step explanation:

We need to find the distance between each pair

a) A (5, 4) and B( 5, -2)

the distance formula is:

$d(A,B) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = 5, x₂=5 and y₁= 4 and y₂= -2

$d(A,B) = \sqrt{(5-5)^2+(-2-4)^2}$

$d(A,B) = \sqrt{(0)^2+(-6)^2}$

$d(A,B) = \sqrt{36}$

$d(A,B) = 6$

Distance between points A (5, 4) and B( 5, -2) is 6 units

b) E (-2, -1) and F( -2, -5)

the distance formula is:

$d(E,F) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = -2, x₂=-2 and y₁= -1 and y₂= -5

$d(E,F) = \sqrt{(-2-(-2))^2+(-5-(-1))^2}$

$d(E,F) = \sqrt{(0)^2+(-4)^2}$

$d(E,F) = \sqrt{16}$

$d(E,F) = 4$

Distance between points E (-2, -1) and F( -2, -5) is 4 units

c) C (-4, 1) and D( 1, 1)

the distance formula is:

$d(C,D) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = -4, x₂=1 and y₁= 1 and y₂= 1

$d(C,D)= \sqrt{(1-(-4))^2+(1-(1))^2}$

$d(C,D) = \sqrt{(5)^2+(0)^2}$

$d(C,D) = \sqrt{25}$

$d(C,D) = 5$

Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) G(3, -5) and H(6, -5)

the distance formula is:

$d(G,H) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = 3, x₂=6 and y₁= -5 and y₂= -5

$d(G,H)= \sqrt{(6-(3))^2+(-5-(-5))^2}$

$d(G,H) = \sqrt{(3)^2+(0)^2}$

$d(G,H) = \sqrt{9}$

$d(G,H) = 3$

Distance between points G(3, -5) and H(6, -5) is 3 units

8 0

3 years ago

Solve for X

Stella [2.4K]

Answer:

C. 9

Step-by-step explanation:

The measure of a triangle is 180.

Make all the angles equal 180.

50+80+6x-4=180.

Solve.

6x=54

x=9

4 0

3 years ago

Read 2 more answers

Each side of a square calendar is 19 inches long. What is the calendar's perimeter?

liberstina [14]

Answer:

a square has 4 sides each of those sides is 19in long perimeter is all around the square so you would add 19+19+19+19=79in

6 0

3 years ago

Read 2 more answers

Use the equation below to find y, if m=7, x=6, and b=2.<br> y=mx+b

Dahasolnce [82]

Answer:

y=44

Step-by-step explanation:

y=mx+b you do substition and replace m with 7 and b with 2 and x with 6

y=7*6+2

the solve with system of order 7 times 6 which is 42 then add the 2 and then you get 44

6 0

3 years ago