Answer:
<em>7,078,912 cents</em>
Step-by-step explanation:
Given the formula for calculating the value of the account in t years as;
V = Pe^rt
P is the principal initially invested
e is the base of a natural logarithm,
r is the rate of interest
t is the time
Given
P = $51200
r = 5.4% = 0.054
t = 6years
Substitute
V = 51200e^(0.054)(6)
V = 51200e^(0.324)
V = 51200(1.3826)
V = $70,789.12
V = 7,078,912 cents
<em>hence the amount in the account after 6 years to the nearest cent is 7,078,912 cents</em>
Answer:
k=32
Step-by-step explanation:
Given the points:
The first step is to find the <u>Centroid</u> of the triangle.
Centroid, X
Next, let P be a point (x,y)
Using the <u>distance formula, </u>
<u />
<u />
<u />
On Substitution into: 
![(x-4)^2+(y-(-1))^2+(x-6)^2+(y-2)^2+(x-(-1))^2+(y-2)^2=3[(x-3)^2+(y-1)^2]+k](https://tex.z-dn.net/?f=%28x-4%29%5E2%2B%28y-%28-1%29%29%5E2%2B%28x-6%29%5E2%2B%28y-2%29%5E2%2B%28x-%28-1%29%29%5E2%2B%28y-2%29%5E2%3D3%5B%28x-3%29%5E2%2B%28y-1%29%5E2%5D%2Bk)
Let us simplify the LHS first
Also, the Right Hand Side
![RHS:3[(x-3)^2+(y-1)^2]+k\\=3[x^2-6x+9+y^2-2y+1]+k\\=3x^2-18x+27+3y^2-6y+3+k\\=3x^2+3y^2-18x-6y+30+k](https://tex.z-dn.net/?f=RHS%3A3%5B%28x-3%29%5E2%2B%28y-1%29%5E2%5D%2Bk%5C%5C%3D3%5Bx%5E2-6x%2B9%2By%5E2-2y%2B1%5D%2Bk%5C%5C%3D3x%5E2-18x%2B27%2B3y%5E2-6y%2B3%2Bk%5C%5C%3D3x%5E2%2B3y%5E2-18x-6y%2B30%2Bk)
Therefore:
Starting with <em>n</em> = 1, the first sequence is given by
(<em>n</em> - 1)/<em>n</em>
since 0 = (1 - 1)/1, and each successive term has a numerator that is 1 less than the denominator.
The second sequence is
1/(3<em>n</em>)
since each denominator is a positive multiple of 3.
2|y+ 3| = 8
|y+3| = 4
y = 1, 7 or -7
hope this helps
