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Charra [1.4K]
3 years ago
14

Help with question. 6

Mathematics
1 answer:
grin007 [14]3 years ago
8 0

This is science not mathematics and also I think the answer is A

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Write an expression that represent the sum of a number and 12
antiseptic1488 [7]

Answer:

5+12

there is no equals sign in an expression so it is just that



6 0
3 years ago
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There is a list of seven numbers. The average of the first four numbers is 5, and the average of the last four numbers is 8. If
sammy [17]

Answer:

6

Step-by-step explanation:

Sum of first 4 numbers= 4*5= 20

This includes 3 + 4th number

Sum of last 4 numbers= 4*8= 32

This includes 4th number + 3

Sum of 7 numbers= 7*(6+4/7)= 46

This includes 3+4th number +3

Number common to both sets= (20+32)- 46 = 6

3 0
3 years ago
A) Simplify<br> X-2<br> 7(x - 2)2
STatiana [176]

Answer:

7x^2 -28x +28

Step-by-step explanation:

7(x - 2)^2

7 ( x-2)(x-2)

Foil

7 ( x^2 -2x-2x+4)

Combine like terms

7( x^2 -4x+4)

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7x^2 -28x +28

6 0
4 years ago
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Can someone please help and solve these 2 problems?
VladimirAG [237]

Answer:

8 for 1

n is (0;8)

Step-by-step explanation:

look photo, but I'm not conviniat if n can be negative, if yes, i hope you will correct me

8 0
3 years ago
A square pyramid has a base with an area of 20 square meters, and its lateral faces have a slant height of x meters. Sydney is c
svetoff [14.1K]
1. Consider the pyramid ABCDE in the figure 1 attached:

Each side of the square base equals \sqrt{20} = \sqrt{4*5} = \sqrt{4}* \sqrt{5}=2 \sqrt{5} (units)

Area of 1 lateral side of pyramid ABCDE is \frac{1}{2}* 2 \sqrt{5}*x=\sqrt{5}x

so the total lateral area is 4\sqrt{5}x (units squared)

and the total surface area is 20+4\sqrt{5}x (units squared)

2. Now consider the second figure KLMNP, Sydney's pyramid:

The lateral area is 4* \frac{1}{2}* 4 \sqrt{5} *2x=16 \sqrt{5}x

so the total area of the second pyramid is 20+16 \sqrt{5}x

So 2 things can be said about the areas:

i) the lateral area of Sydney's pyramid is \frac{16 \sqrt{5}x}{4\sqrt{5}x} =4 times larger than the lateral area of the original pyramid.

ii) The total area of Sydney's pyramid is (20+16 \sqrt{5}x)-(20+4\sqrt{5}x)=12\sqrt{5}x units squared larger than the total area of the original pyramid.

5 0
3 years ago
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