Help with question. 6

For questions 1-3

umka2103 [35]

1) A 2) C 3) D

These are the answers

6 0

3 years ago

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Equation of line M is Y=5/8x+1 . Line N is perpendicular to M. What is the slope of line N?

jasenka [17]

Answer:

To be honest just think there´s no right or wrong answer (Hope i helped you Alot)

Step-by-step explanation:

7 0

3 years ago

The graph below shows the line of best fit for data collected on the number of cell phones and cell phone cases sold at a local

Dovator [93]

Answer:

C

Step-by-step explanation:

The equation of a line is given by $y-y_1=m(x-x_1)$

and

slope (m) is given by:

$m=\frac{y_2-y_1}{x_2-x_1}$

Where (x_1,y_1) are the first set of point in the line and (x_2,y_2) is the second set of point

Let's take 2 points arbitrarily. (0,0) & (25,20)

Let's plug it and find the equation:

$m=\frac{20-0}{25-0}=0.8$

Now

$y-y_1=m(x-x_1)\\y-0=0.8(x-0)\\y=0.8x$

C is the correct answer.

5 0

3 years ago

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18=3(3x-6) 4x+6+3=17

klio [65]

Answer:

3(3x -6)=9x-18

4x +6+3=4x +9

7 0

3 years ago

The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 1700 vot

lara [203]

Answer:

$z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562$

$p_v =P(z>2.562)=0.0052$

So the p value obtained was a very low value and using the significance level given $\alpha=0.02$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

Step-by-step explanation:

Data given and notation

n=1700 represent the random sample taken

$\hat p=0.66$ estimated proportion of voters that favored construction

$p_o=0.63$ is the value that we want to test

$\alpha=0.02$ represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that percentage of residents who favor construction is more than 63%.:

Null hypothesis: $p \leq 0.63$

Alternative hypothesis: $p > 0.63$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.02$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.562)=0.0052$

So the p value obtained was a very low value and using the significance level given $\alpha=0.02$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

7 0

3 years ago