All categories

2 years ago

Hiii can someone help me please it’s really greatly appreciated!!THANK YOUUU

Mathematics

1 answer:

-Dominant- [34]2 years ago

3 0

Answer:

Step-by-step explanation:

so we know that a triangle degrees have to add up to 180 in the inside right? So we know c is 90 and so you need to find A and B. The left over degrees you have is 90 so the sum of B and A would have to be 90, thats all i can help you with sorry.

You might be interested in

Write a word phrase to represent the algebraic expressions 2x + 4

Yuki888 [10]

When i babysit, i get 4 dollars for showing up, and them 2 dollars for every hour that im there. X=hours

7 0

3 years ago

Read 2 more answers

When is a lower annual interest fee better than a low annual fee

sertanlavr [38]

hope it helps.........

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%2832%29%5E%7B1%2F5%7D" id="TexFormula1" title="(32)^{1/5}" alt="(32)^{1/5}" align="absmiddle"

lorasvet [3.4K]

Answer:

Step-by-step explanation:

${32}^{ \frac{1}{5} }$

$= \sqrt[5]{32}$

$= \sqrt[5]{2 \times 2 \times 2 \times 2 \times 2}$

= 2 (Ans)

4 0

2 years ago

Rebecca is three years younger than twice Anthony's age. Write an expression that represents the relationship of Rebecca's age i

Andrei [34K]

Answer:

X=2y-3

Step-by-step explanation:

Let Rebecca's age be x

Let Anthony's age be y

Twice Anthony =2y

Rebecca's age (x) to be 3 years younger than twice Anthony's =2y-3

So, it's x=2y-3

4 0

3 years ago

A researcher wishes to estimate the average blood alcohol concentration (BAC) for drivers involved in fatal accidents who are f

Mnenie [13.5K]

Answer:

A 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

Step-by-step explanation:

We are given that a researcher randomly selects records from 60 such drivers in 2009 and determines the sample mean BAC to be 0.16 g/dL with a standard deviation of 0.080 g/dL.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean BAC = 0.16 g/dL

s = sample standard deviation = 0.080 g/dL

n = sample of drivers = 60

$\mu$ = population mean BAC in fatal crashes

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 90% confidence interval for the population mean, $\mu$ is;

P(-1.672 < $t_5_9$ < 1.672) = 0.90 {As the critical value of t at 59 degrees of

freedom are -1.672 & 1.672 with P = 5%} P(-1.672 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.672) = 0.90

P( $-1.672 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $0.16-1.672 \times {\frac{0.08}{\sqrt{60} } }$ , $0.16+1.672 \times {\frac{0.08}{\sqrt{60} } }$ ]

= [0.143, 0.177]

Therefore, a 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

7 0

3 years ago