The answer is C. That would be ur answer
Answer:
Part A. C=9
Part B. (w+3)² =139
Part C. w = 8.8 inch
Step-by-step explanation:
Given from the question length of the the picture = (2w+12) inches
Width of the picture = w inches
Area of the picture = 260 inch²
Part A. Area of the picture with the given dimensions= w×(2w+12)
Or w(2w+12) = 260
2w²+12w = 260
2(w²+6w) = 2×(130)
w²+6w = 130
Or w²+6w +9 = 130+9 ⇒ which is in the form of w²+6w+c = 130+c
Therefore for c = 9 we will get a perfect square trinomial.
Part B. As we have seen the equation in part A.
As required equation will be (w+3)²=139
Part C. Since (w+3)² = 139
Then by taking under root on both the sides of the equation
(w+3) =√139 = 11.8
(w+3)-3=11.8-3
w = 8.8 inch
Answer:
f=2
Step-by-step explanation:
3=9-3f
3-9=-3f
-6=-3f
2=f
f=2
Step-by-step explanation:
Move expression to the left side and change its sign
5
y
−
3
+
10
y
2
−
y
−
6
−
y
y
+
2
=
0
Write
−
y
as a sum or difference
5
y
−
3
+
10
y
2
+
2
y
−
3
y
−
6
−
y
y
+
2
=
0
Factor out
y
and
−
3
from the expression
5
y
−
3
+
10
y
(
y
+
2
)
−
3
(
y
+
2
)
−
y
y
+
2
=
0
Factor out
y
+
2
from the expression
5
y
−
3
+
10
(
y
+
2
)
(
y
−
3
)
−
y
y
+
2
=
0
Write all numerators above the least common denominator
5
(
y
+
2
)
+
10
−
y
(
y
−
3
)
(
y
+
2
)
(
y
−
3
)
=
0
Distribute
5
and
−
y
through the parenthesis
5
y
+
10
+
10
−
y
2
+
3
y
(
y
+
2
)
(
y
−
3
)
=
0
Collect the like terms
8
y
+
20
−
y
2
(
y
+
2
)
(
y
−
3
)
=
0
Use the commutative property to reorder the terms
−
y
2
+
8
y
+
20
(
y
+
2
)
(
y
−
3
)
=
0
Write
8
y
as a sum or difference
−
y
2
+
10
y
−
2
y
+
20
(
y
+
2
)
(
y
−
3
)
=
0
Factor out
−
y
and
−
2
from the expression
−
y
(
y
−
10
)
−
2
(
y
−
10
)
(
y
+
2
)
(
y
−
3
)
=
0
Factor out
−
(
y
−
10
)
from the expression
−
(
y
−
10
)
(
y
+
2
)
(
y
+
2
)
(
y
−
3
)
=
0
Reduce the fraction with
y
+
2
−
y
−
10
y
−
3
=
0
Determine the sign of the fraction
−
y
−
10
y
−
3
=
0
Simplify
10
−
y
y
−
3
=
0
When the quotient of expressions equals
0
, the numerator has to be
0
10
−
y
=
0
Move the constant,
10
, to the right side and change its sign
−
y
=
−
10
Change the signs on both sides of the equation
y
=
10
Check if the solution is in the defined range
y
=
10
,
y
≠
3
,
y
≠
−
2
∴
y
=
10
