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katrin2010 [14]
3 years ago
8

If your front lawn is 24.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1050 new snow flakes every min

ute, how much snow (in kilograms) accumulates on your lawn per hour? assume an average snow flake has a mass of 1.70 mg.
Mathematics
1 answer:
geniusboy [140]3 years ago
5 0
First find the area of the front lawn:
Area = length * width
Area = 24.0ft * 20.0ft
Area = 480ft^2

Next, find the weight in kilograms of the snow per square foot per hour per ft^2:
weight\ per\ ft^{2}=\frac{1050\ snowflakes}{minute}\\\\weight\ per\ ft^{2}=\frac{1050\ snowflakes}{minute}*\frac{1.70\ milligrams}{snowflake}*\frac{1\gram}{1000\milligrams}*\frac{1\kilogram}{1000\grams}* \frac{60\minutes}{1\hour}\\\\weight\ per\ ft^{2}=\frac{1050*1.70}{1000*1000*60}*\frac{kg}{hour}=2.975*10^{-5}\ \frac{kg}{hour}\\\\weight=2.975*10^{-5}\ \frac{kg}{hour*ft^{2}}

Now multiply the area of the lawn by the weight of the snow per hour per ft^2:
weight\ of\ snow=lawn\ area*weight\ per\ hour\ per ft^{2}\\\\weight=480\ ft^{2}*2.975*10^{-5}\ \frac{kg}{hour*ft^{2}}\\\\weight=0.01428\ \frac{kg}{hour}



Thus your answer is .01428 kg.
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liberstina [14]

First, given graph is very inaccurate. I suppose that you made net with pen.

a) The slope is the angle ( tan∡) between your graph and x axis.

The slope represent the level of the earnings growth.

b) According to the given graph y-intercept= 30$

Y-intercept represent starting amount of money.

c) If we accept that y=70 is connected with x=2 and y=30 with x=0

The  slope is S= (70-30)/2= 40/2=20

Linear equation for this function is

y= 20x+30

d) When we replace y=300$ in the equation we get

20x+30=300 => 20x=300-30 => 20x=270 => x=270/20=13.5h

x=13.5h

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3 years ago
What is the value of 5 in each of this number 25
Yuri [45]
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Which of the following points is in the solution set of y>-x² + 5?
eimsori [14]
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7 0
2 years ago
A-One Talent Agency has 108 clients. 42 of the clients play piano and 51 of the clients play guitar.
Butoxors [25]

Thwre are 28 clients who don not play any of the instrument using the principle of Venn distribution.

<u>Using a Venn diagram analogy</u> :

  • Total number of client, U = 108
  • Piano, P = 42
  • Guitar, G = 51
  • Piano and Guitar, (PnG) = 13
  • None =?

<u>From the information given</u> :

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<u>The total number of clients can be related thus</u> :

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108 = 29 + 38 + 13 + None

108 = 80 + None

None = 108 - 80

None = 28

Therefore, the number of clients who do not play any of the instruments is 28

Learn more :brainly.com/question/12570490

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Foci of ellipse of 3x2 + y2 =9
Oksi-84 [34.3K]

Answer:

x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3

Step-by-step explanation:

Let's solve for x.

3x2+y2=9

Step 1: Add -y^2 to both sides.

3x2+y2+−y2=9+−y2

3x2=−y2+9

Step 2: Divide both sides by 3.

3x^2/3= -y^2+9/3

x^2=-1/3 y^2 +3

x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3

Hope it helped!

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