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3 years ago

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The area of a rectangular pool is given by the trinomial 2y2 + 5y – 42. What are the possible dimensions of the pool? Use factor

ing.
A. 2y + 7 and y – 6
B. 2y – 2 and y + 6
C. –2y – 7 and –y – 6
D. 2y – 7 and y + 6

1 answer:

arsen [322]3 years ago

3 0

Answer:

D is your answer

Step-by-step explanation:

(2y-7) (y+6) that is my answer and it matches with D promise 100%

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The length and breath of a rectangle are (a^2 +ab +b^2) units and (a-b) units.Find the area of the rectangle.

pshichka [43]

Answer:

a^3 - b^3.

Step-by-step explanation:

Area = length * breadth

= (a - b)(a^2 + ab + b^2)

= a(a^2 + ab + b^2) - b(a^2 + ab + b^2)

= a^3 + a^2b + ab^2 - a^2b - ab^2 - b^3

Note: the 4 middle terms cancel out. So the answer is

a^3 - b^3.

4 0

3 years ago

HEY GUYS I NEED THIS ANSWER NOW

Sergio [31]

Let

x-------> the number of fiction books

y-------> the number of nonfiction books.

we know that

$x+y=26$ -----> equation $1$

$x=y+12$

$x-y=12$ -----> equation $2$

Add equation $1$ and equation $2$

$x+y=26\\x-y=12\\ ------\\ 2x=38\\ x=38/2\\x=19\ fiction\ books$

<u>find the value of y</u>

$x+y=26$

$19+y=26$

$y=26-19=7\ nonfiction\ books$

therefore

<u>the answer is</u>

Part a) the number of fiction books is $19\ fiction\ books$

Part b) the number of nonfiction books is $7\ nonfiction\ books$

6 0

3 years ago

Read 2 more answers

Find the area of the shaded regions:

Crank

First, we'll find the area of the large section, including the smaller section that is white.

Area of a circle: pi x r^2

A = pi x 7^2

A = 49pi x 120/360

A = 49/3 pi cm^2

Now, we'll find the area of the small section.

A = pi x 3^2

A = 9 pi x 120/360

A = 3pi cm^2

All that's left to do now is subtract.

49/3 pi - 3 pi

40/3 pi cm^2

(or 13 1/3 = 13.33 cm^2)

Hope this helps!

6 0

3 years ago

During one waiters shift he delivered 13 appetizers, 17 entrées, and 10 desserts what percentage of the dishes he delivered were

Triss [41]

Question

During one waiters shift he delivered 13 appetizers, 17 entrées, and 10 desserts what percentage of the dishes he delivered were: A. Desserts B. Appetizers C. entrees

Answer:

A)Desserts = 25 %

B)Appetizers = 32.5 %

C)Entrées = 32.5 %

Step-by-step explanation:

<u>Given:</u>

Number of appetisers = 13

Number of entrees = 17

Number of desserts = 10

<em><u>A. percentage of the dishes he delivered were Desserts</u></em>

Percentage of Desserts = $\frac{\text{ Number of dessert}}{\text{ total number of dishes}} \times 100$

Total number of dishes = 13 + 17 + 10 = 40

Percentage of Desserts = $\frac{10}{40} \times 100$

Percentage of Desserts = $0.25 \times 100$

Percentage of Desserts = 25 %

<em><u>B. percentage of the dishes he delivered were Appetizers </u></em>

Percentage of Desserts = $\frac{\text{ Number of Appetizers }}{\text{ total number of dishes}} \times 100$

Percentage of Desserts = $\frac{13}{40} \times 100$

Percentage of Desserts = $0.325 \times 100$

Percentage of Desserts = 32.5 %

<em><u>C. percentage of the dishes he delivered were Entrées </u></em>

Percentage of Desserts = $\frac{\text{ Number of Entrees }}{\text{ total number of dishes}} \times 100$

Percentage of Desserts = $\frac{17}{40} \times 100$

Percentage of Desserts = $0.425 \times 100$

Percentage of Desserts = 42.5 %

7 0

3 years ago

In a pack of pretzel sticks, one-quarter of the total number of pretzel sticks is 14.

DanielleElmas [232]

Answer:

6 lol have a good day

6 0

3 years ago

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