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3 years ago

Solve it using Pythagoras theorem plzz help I will mark u brainliest

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

6 0

Answer:

Reasoning:

(7^2)-(3^2)= (6.32^2)

(6.32^2)+(6^2)=(8.72^2)

I hope this helps and good luck

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Can someone please help, I'll give brainliest!!! WORTH 40 PTS!

Studentka2010 [4]

Answer:

X = 14.48528137

Step-by-step explanation:

ADD 72 TO BOTH SIDES
SQUARE ROOT 72
ADD 6
X = 14.48528137

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2 years ago

Helppppppppppppppppppppp!!!!

Inessa [10]

Answer:

±i√55

Step-by-step explanation:

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3 years ago

Simplify by dividing (-5/8)÷(-3/4)

Olenka [21]

Here pls give brainliest

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2 years ago

Read 2 more answers

How do I find the integral<br> ∫10(x−1)(x2+9)dxint10/((x-1)(x^2+9))dx ?

defon

$\int\frac{10}{(x-1)(x^2+9)}\ dx=(*)\\\\\frac{10}{(x-1)(x^2+9)}=\frac{A}{x-1}+\frac{Bx+C}{x^2+9}=\frac{A(x^2+9)+(Bx+C)(x-1)}{(x-1)(x^2+9)}\\\\=\frac{Ax^2+9A+Bx^2-Bx+Cx-C}{(x-1)(x^2+9)}=\frac{(A+B)x^2+(-B+C)x+(9A-C)}{(x-1)(x^2+9)}\\\Updownarrow\\10=(A+B)x^2+(-B+C)x+(9A-C)\\\Updownarrow\\A+B=0\ and\ -B+C=0\ and\ 9A-C=10\\A=-B\ and\ C=B\to9(-B)-B=10\to-10B=10\to B=-1\\A=-(-1)=1\ and\ C=-1$

$(*)=\int\left(\frac{1}{x-1}+\frac{-x-1}{x^2+9}\right)\ dx=\int\left(\frac{1}{x-1}-\frac{x+1}{x^2+9}\right)\ dx\\\\=\int\frac{1}{x-1}\ dx-\int\frac{x+1}{x^2+9}\ dx=\int\frac{1}{x-1}-\int\frac{x}{x^2+9}\ dx-\int\frac{1}{x^2+9}\ dx=(**)\\\\\#1\ \int\frac{1}{x-1}\ dx\Rightarrow\left|\begin{array}{ccc}x-1=t\\dx=dt\end{array}\right|\Rightarrow\int\frac{1}{t}\ dt=lnt+C_1=ln(x-1)+C_1$

$\#2\ \int\frac{x}{x^2+9}\ dx\Rightarrow \left|\begin{array}{ccc}x^2+9=u\\2x\ dx=du\\x\ dx=\frac{1}{2}\ du\end{array}\right|\Rightarrow\int\left(\frac{1}{2}\cdot\frac{1}{u}\right)\ du=\frac{1}{2}\int\frac{1}{u}\ du\\\\\\=\frac{1}{2}ln(u)+C_2=\frac{1}{2}ln(x^2+9)+C_2$

$\#3\ \int\frac{1}{x^2+9}\ dx=\int\frac{1}{x^2+3^2}\ dx=\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3\\\\therefore:\\\\\#1;\ \#2;\ \#3\Rightarrow(**)=ln(x-1)+C_1-\frac{1}{2}ln(x^2+9)+C_2-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3$

$\boxed{=ln(x-1)-\frac{1}{2}ln(x^2+9)-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C}$

4 0

3 years ago

Whats the equation of a line with slope 3/5 that passes through the point (15,8)

Elden [556K]

Answer:

y=3/5x-1

Step-by-step explanation:

The formula you need to find this would be

(y-y1)=m(x-x1)

The y1 is your y point.

The x1 is your x point.

m is your slope.

Start by plugging in your numbers that they provide you.

(y-8)=3/5(x-15)

Now you need to distribute the slope to the terms inside the parenthesis next to it.

3/5(x)=3/5x

3/5(-15)= -9 Now you put those back into the equation.

(y-8)=3/5x-9

At this point you can get rid of the parenthesis around the y-8 since it is basically saying to take the term times 1.

To get y alone we not need to add 8 to both sides.

y-8=3/5x-9

+8 +8

y=3/5x-1

3 0

3 years ago

Solve it using Pythagoras theorem plzz help I will mark u brainliest ​

Solve it using Pythagoras theorem plzz help I will mark u brainliest