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DochEvi [55]
3 years ago
5

Jessica and Lindsay are curious as to who owns the most pairs of shoes. Jessica counter shoes and finds that she owns 18 pairs o

f shoes. When Lindsay counts hers, she finds that she owns only approx 72% as many as jessica. How many pairs of shoes does she own?
Mathematics
1 answer:
malfutka [58]3 years ago
4 0

Answer: 13 pairs

Step-by-step explanation:

Given

Jessica owns 18 pairs of shoes

Lindsay has 72% as many as Jessica

So, the number of pairs Lindsay owns

\Rightarrow 72\%\ \text{of}\ 18=0.72\times 18\\\\\Rightarrow 12.96\approx 13\ \text{pairs}

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nordsb [41]
4.29 + 97.2 + 0.687 = 102.177

In adding decimal numbers, make sure that the decimal points are aligned. Since each number has different counts of numbers after the decimal point, use 0 to pad the missing places.
    
      4.290
    97.200
   <u>   0.687
</u>  102.177

The count of numbers after the decimal point is the same count of number of the decimal who has the greatest count of number after the decimal point.

4.29 only has 2 counts of places after the decimal point
97.2 only has 1 count of place after the decimal point
0.687 has 3 counts of places after the decimal point. 

The sum of the decimals must also have 3 counts of places after the decimal point.

7 0
3 years ago
Please help me with these, oh sweet jesus
Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

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7 0
3 years ago
I confused on this question
Fynjy0 [20]
42 degrees. Comment down if you need the explanation why
6 0
3 years ago
Read 2 more answers
-0.2 + 7/10 plz help I’m stuck
Lelechka [254]

(-0.2) + (7÷10) =

(-0.2) + 0.70 =

0.5

Hope that helps!


6 0
3 years ago
Evaluate 17s^2 + 32s +180
dezoksy [38]
Answer: 66s + 180

How:

17 s ^ { 1 } 2 + 32 s + 180
Calculate s to the power of 1 and get s.

17s\times 2+32s+180
Multiply 17 and 2 to get 34.

34s+32s+180
Combine 34s and 32s to get 66s.

Final answer should be 66s + 180
7 0
3 years ago
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