Answer:
Step-by-step explanation:
T = 4c + 25....where c = # of classes and T = total cost
2 classes...so sub in 2 for c and solve for T
T = 4(2) + 25
T = 8 + 25
T = 33 <==== with 2 classes ,its $ 33
4 classes....so sub in 4 for c and solve for T
T = 4(4) + 25
T = 16 + 25
T = 41 <==== with 4 classes, its $ 41
8 classes....sub in 8 for c
T = 4(8) + 25
T = 32 + 25
T = $ 57 <==== with 8 classes, its $ 57
10 classes...sub in 10 for c
T = 4(10) + 25
T = 40 + 25
T = 65 <===== with 10 classes, its $ 65
Answer:
Check below, please
Step-by-step explanation:
Step-by-step explanation:
1.For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.)
When the derivative of a function is equal to zero, then it occurs when we have either a local minimum or a local maximum point. So for our x-coordinates we can say

2. For which values of x is f '(x) positive?
Whenever we have

then function is increasing. Since if we could start tracing tangent lines over that graph, those tangent lines would point up.

3. For which values of x is f '(x) negative?
On the other hand, every time the function is decreasing its derivative would be negative. The opposite case of the previous explanation. So

4.What do these values mean?

5.(b) For which values of x is f ''(x) zero?
In its inflection points, i.e. when the concavity of the curve changes. Since the function was not provided. There's no way to be precise, but roughly
at x=-4 and x=4
The answer is: A - f(x) = 1/2 cos (x)
Answer:
D
Step-by-step explanation:
The equations are
● 4x + 2y = 10 (1)
● 4x - 2y = -10 (2)
● 4x + 2y = 10
Add - 4x to both sides
● 4x + 2y -4x = 10 -4x
● 2y = 10 -4x
Divide both sides by 2
● 2y/2 = (10 - 4x)/2
● y = 5 - 2x
● y = -2x + 5 (1)
● 4x - 2y = -10
Add -4x to both sides
● 4x -2y -4x = -10 - 4x
● -2y = -10 - 4x
Divide both sides by -2
● -2y/-2 = (-10 -4x)/-2
● y = 10 + 2x
● y = 2x + 5 (2)
So the equation are
● y = 2x + 5
● y = -2x + 5
Graph them
The lines intersect at (0,5) but aren't perpendicular
So the answer is d