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Rama09 [41]
3 years ago
7

Hcf of 30 , 15 and 25

Mathematics
1 answer:
kolezko [41]3 years ago
4 0

Answer:

Step-by-step explanation:

The Greates Common Factor (GCF) is:   3 x 5 = 15

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A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and
pav-90 [236]

Answer:

ans=13.59%

Step-by-step explanation:

The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean \mu and standard deviation \sigma, we have these following probabilities

Pr(\mu - \sigma \leq X \leq \mu + \sigma) = 0.6827

Pr(\mu - 2\sigma \leq X \leq \mu + 2\sigma) = 0.9545

Pr(\mu - 3\sigma \leq X \leq \mu + 3\sigma) = 0.9973

In our problem, we have that:

The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months

So \mu = 53, \sigma = 11

So:

Pr(53-11 \leq X \leq 53+11) = 0.6827

Pr(53 - 22 \leq X \leq 53 + 22) = 0.9545

Pr(53 - 33 \leq X \leq 53 + 33) = 0.9973

-----------

Pr(42 \leq X \leq 64) = 0.6827

Pr(31 \leq X \leq 75) = 0.9545

Pr(20 \leq X \leq 86) = 0.9973

-----

What is the approximate percentage of cars that remain in service between 64 and 75 months?

Between 64 and 75 minutes is between one and two standard deviations above the mean.

We have Pr(31 \leq X \leq 75) = 0.9545 = 0.9545 subtracted by Pr(42 \leq X \leq 64) = 0.6827 is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.

To find just the percentage above the mean, we divide this value by 2

So:

P = {0.9545 - 0.6827}{2} = 0.1359

The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.

4 0
3 years ago
Wendy is paid $12 per hour and plans to work between 30 and 25 hours per week identify the independent and dependent quantity in
zheka24 [161]
So first uadd 30 with 25 the the answer u get u multiply with 12 hope that helps
8 0
3 years ago
Line g is dilated by a scale factor of 1/2 from the origin to create line g'. Where are points E' and F' located after dilation,
Sholpan [36]

Answer:

The locations of E' and F' are E'(-2,0) and F'(0,1), and lines g and g' are parallel.

Step-by-step explanation:

I got it right on my test! :)

7 0
2 years ago
How many toes do i have? giving brainiest if right!
yanalaym [24]
10 toesssssssssssssssssssssssss
5 0
3 years ago
Hellpppp pls!!!!!!!!!!!!
yarga [219]

Answer:

2a+6b

Step-by-step explanation:

3 0
3 years ago
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